There are basically two groups.
A group of 5 shorter players, which can be arranged themselves in 5! ways in front row
A group of 4 taller players, of which one player who is mischievous would stand right next to the coach. Remaining 3 taller players can be arranged themselves in 3! ways.
The coach will be in the middle of the taller players and the mischievous player can stand at right or at left of the coach. So we have to consider both these scenarios.
Arrangement of 5 shorter players in front row AND Arrangement of 3 taller players in back row(when mischievous player is to the immediate left of the coach) OR Arrangement of 5 shorter players in front row AND Arrangement of 3 taller players in back row(when mischievous player is to the immediate right of the coach)
We know in Permutations, Combinations, and Probability, AND stands for Multiplication and OR stands for Addition
Arrangement of 5 shorter players in front row * Arrangement of 3 taller players in back row(while mischievous player is to the immediate left of the coach) + Arrangement of 5 shorter players in front row * Arrangement of 3 taller players in back row(while mischievous player is to the immediate right of the coach)
5! * 3! + 5! * 3! ----------> 2(5!3!) -------> 1440 ------Choice D
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