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A photographer will arrange 6 people of 6 different heights

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Intern
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Joined: 28 Oct 2014
Posts: 36

Kudos [?]: 82 [0], given: 5

Location: India
GMAT 1: 640 Q50 V27
GMAT 2: 680 Q50 V30
GPA: 3.89
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User
Re: A photographer will arrange 6 people of 6 different heights [#permalink]

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New post 12 Mar 2017, 07:14
srini123 wrote:
I got 6 as answer too, manually arranging assuming 1,2,3,4,5,6 as heights (since each is different from other)

so possible positions are as below:

456 436
123 125

346 356
125 124

246 256
135 134

Kalpesh logic looks right to me... and is faster than listing possibilities



436
125 is not a valid combination. The order should be in ascending order in each row.

Kudos [?]: 82 [0], given: 5

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Joined: 02 Oct 2011
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Kudos [?]: 5 [0], given: 129

Location: Thailand
Concentration: Strategy, Finance
GMAT 1: 560 Q47 V20
GPA: 3.26
GMAT ToolKit User Premium Member
Re: A photographer will arrange 6 people of 6 different heights [#permalink]

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New post 23 Jul 2017, 01:23
So i guess its trail and error for this question....
BTW I got this Q in during my mock test on GMATPrep EP1 Exam 4.
This one popped up after I got 6 corrects and ended my first 10 streak T___T

Anyway just watch out if you are planning to do EP1 for mocks.

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Re: A photographer will arrange 6 people of 6 different heights [#permalink]

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New post 28 Jul 2017, 10:04
Sorry i am still not understanding this question. I considered the height of the 6 people to be 1,2,3,4,5,6 and so R2(Row 2) has 4,5,6 and R1 (Row 1) has 1, 2,3 this is the only possible way right because the question also says that the height within the row must be increasing from left to right. Where am i going wrong in my understanding of the question. Thank you

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Re: A photographer will arrange 6 people of 6 different heights [#permalink]

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New post 29 Sep 2017, 19:12
Does this perchance use somewhat of the same logic as the question that ask something along the lines of "how many combinations have Lisa to the right of George"? In those cases, you simply halve the combinatorics problem.

In this case, I figured you could get 6c3 = 20 different groups of three from six people. Then, half of these (10) would have taller people in back. Then, half of those (5) would have each row in the correct order.

Luck, or logic?

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Re: A photographer will arrange 6 people of 6 different heights [#permalink]

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New post 17 Nov 2017, 22:51
Hi Folks,

Just wanted to share my trick to solve this problem.

To answer this choice, you need to know that the positions of 1 and 6 are fixed because they are the lowest and highest.
x y 6
1 v w

v, w, x and y can be any number that create possibility
Therefore, we need to see check the possibility by trial.
The trick here is only v and w that are in play here --> x and y will be automatically fitted from the rule.

Case 1 v,w = 2 and 3
_ _ 6
1 2 3

we got
4 5 6
1 2 3

Case II v,w = 2 and 4
_ _ 6
1 2 4

we got
3 5 6
1 2 4

Case III v,w = 2 and 5
_ _ 6
1 2 5

we got
3 4 6
1 2 5

Case IV v,w = 3 and 4
_ _ 6
1 3 4

we got
2 5 6
1 3 4

Case V v,w = 3 and 5
_ _ 6
1 3 5

we got
2 4 6
1 3 5

Case VI v,w = 4 and 5
_ _ 6
1 4 5

we are left with 2 and 3 which both are less than 4

So, Case VI is no longer valid
Ultimately, we got 5 cases.

Hope this help

Cheers,
Katanyu

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Re: A photographer will arrange 6 people of 6 different heights   [#permalink] 17 Nov 2017, 22:51

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