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26 Jan 2020, 10:17
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65% (01:00) correct
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A plane has six points and no three of the points are collinear. How many distinct triangles can be drawn that have three of the points in the plane as vertices?
A) 15
(B) 18
(C) 20
(D) 30
(E) 216
Source: GMAT Quantum Math Course
A) 15
(B) 18
(C) 20
(D) 30
(E) 216
Source: GMAT Quantum Math Course
26 Jan 2020, 22:51
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sjuniv32
A plane has six points and no three of the points are collinear. How many distinct triangles can be drawn that have three of the points in the plane as vertices?
A) 15
(B) 18
(C) 20
(D) 30
(E) 216
Source: GMAT Quantum Math Course
A) 15
(B) 18
(C) 20
(D) 30
(E) 216
Source: GMAT Quantum Math Course
Explanation:
Selecting 3 points from 6 to form a triangle: 6C3
= 6!/3!*3!
= 6*5*4*3!/3!*3!
= 120/6
= 20 ways
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ajaymahadev
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26 Jan 2020, 22:58
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to make a triangle, we need 3 points. It is given that no 3 points are collinear, which makes things easier for us.
all we have to do is select 3 points out of the 6 points and this can be done in 6C3 ways or 20 ways.
all we have to do is select 3 points out of the 6 points and this can be done in 6C3 ways or 20 ways.
