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10 Feb 2021, 08:45
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
48% (01:31) correct
52%
(01:55)
wrong
based on 151
sessions
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A rack has 5 different pairs of shoes. The number of ways in which 4 shoes can be chosen from it so that there will be no complete pair is:
(A) 1920
(B) 200
(C) 110
(D) 80
(E) 75
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
(A) 1920
(B) 200
(C) 110
(D) 80
(E) 75
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
globaldesi
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10 Feb 2021, 11:06
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select any 4 pair out of those 5 pairs
5C4 = 5
from each pair selected we have 2 ways to select 1 shoe
2*2*2*2
hence total ways = 5*2*2*2*2 = 80
D IMO
5C4 = 5
from each pair selected we have 2 ways to select 1 shoe
2*2*2*2
hence total ways = 5*2*2*2*2 = 80
D IMO
10 Feb 2021, 11:15
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The answer is A 1920 ways.
We have to choose 4 shoes out of 10 ( 5 pairs).
Let us choose 1 by one.
_ _ _ _
For first shoe, available option are 10.
For the second shoe, available option are 8 (10 - (shoe selected + selected shoe's pair)).
Similarly, for third shoe, available options are 6.
And for fourth shoe, available option are 4.
To get the total number of ways, miltiply the above = 10*8*6*4 = 1920
Posted from my mobile device
We have to choose 4 shoes out of 10 ( 5 pairs).
Let us choose 1 by one.
_ _ _ _
For first shoe, available option are 10.
For the second shoe, available option are 8 (10 - (shoe selected + selected shoe's pair)).
Similarly, for third shoe, available options are 6.
And for fourth shoe, available option are 4.
To get the total number of ways, miltiply the above = 10*8*6*4 = 1920
Posted from my mobile device
