theperfectgentleman wrote:

A railroad worker finds himself trapped inside a tunnel at a point that is 25% of the length of the tunnel with a train approaching towards the near end with constant speed. He calculates that if he runs towards the near end doubling his speed then he would just manage to save himself. If on the other hand, he reduced his speed by 25% and ran

towards the far end of the tunnel, then he would also just manage to avert danger. What is the the ratio of the speed of the train to the speed of the worker?

(1) 8 : 7

(2) 7 : 8

(3) 3 : 1

(4) 2 : 1

(5) None of these

rt=rate of train

rw=rate of worker

d=distance from engine to tunnel

t=distance of tunnel

equation1: d/rt=(t/4)/2rw➡

rt/rw=8d/t

equation2: (d+t)/rt=(3t/4)/(3rw/4)➡

rt/rw=t+d/t

8d/t=(t+d)/t➡

8d=t+d➡

t=7d

rt/rw=t+d/t=8d/7d=8:7

(1)