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A recipe for soda requires w litres of water for every litre [#permalink]

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29 Apr 2008, 06:01

8

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A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

65% (02:02) correct
35% (02:14) wrong based on 202 sessions

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A recipe for soda requires w litres of water for every litre of syrup. If soda is made according to this recipe using m litres of syrup, and sold for j dollars a litre, what will be the gross profit if syrup costs k dollars a litre and water costs nothing?

A. m(w+j-k) B. jm[(1/w)+1] C. m(jw-k) D. (j-k)m E. jm(1+w)-km

A recipe for soda requires w litres of water for every liter of syrup. If the soda is made according to this recipe using m litres of syrup, and sold for j dollars a liter, what will be the gross profit if the syrup costs k dollars a liter and water costs nothing ?

m(w+j-k) jm(1/w + 1) m(jw -k) (j-k) m jm(1+w) - km

This is quite confusing,. please help me find the best approach. Thanks

Should be C.

lets say we have 5liters of water for 1 liter of syrup. That means when we have 5 liters of syrup we have 25 liters of water.

A recipe for soda requires w litres of water for every liter of syrup. If the soda is made according to this recipe using m litres of syrup, and sold for j dollars a liter, what will be the gross profit if the syrup costs k dollars a liter and water costs nothing ?

m(w+j-k) jm(1/w + 1) m(jw -k) (j-k) m jm(1+w) - km

This is quite confusing,. please help me find the best approach. Thanks

Answer is E!!

Water for m liters of Syrup = WM So total soda is wm + m liters

Soda is made using m litres of Syrup. THis means m*w litres of water. Therefore total Soda made in litres = w*m+m = m(1+w)

Selling price of soda per litre = j dollars Selling price of m(1+w) litres of soda = j*m(1+w) dollars

Cost of syrup per litre = k dollars Cost of m litres of syrup used = km dollars

Gross Profit = Selling price of Soda - Cost price of Syrup = jm(1+w) - km... (Ans E or 5)
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A recipe for soda requires w litres of water for every litre of syrup. If soda is made according to this recipe using m litres of syrup, and sold for j dollars a litre, what will be the gross profit if syrup costs k dollars a litre and water costs nothing?

A. m(w+j-k) B. jm[(1/w)+1] C. m(jw-k) D. (j-k)m E. jm(1+w)-km

Since soda requires \(w\) liters of water for every liter of syrup, then \(m\) liters of syrup gives \(water+syrup=mw+m\) liters of soda.

Re: A recipe for soda requires w litres of water for every litre [#permalink]

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16 Oct 2017, 03:10

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A recipe for soda requires w litres of water for every litre of syrup. If soda is made according to this recipe using m litres of syrup, and sold for j dollars a litre, what will be the gross profit if syrup costs k dollars a litre and water costs nothing?

A. m(w+j-k) B. jm[(1/w)+1] C. m(jw-k) D. (j-k)m E. jm(1+w)-km

Since every litre of syrup requires w litres of water and there are m litres of syrup, we need mw litres of water, and together with the m litres of syrup, we can make mw + m litres of soda.

Since we are selling the soda for j dollars a litre, we can make j(mw + m) dollars. However, since the syrup costs k dollars a litre (water costs nothing), we have a cost of km dollars. Thus, the total profit from selling the soda is:

j(mw + m) - km = jm(w + 1) - km

Answer: E
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