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# A rectangular park which is 20 feet long and 24 feet wide is to be

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Manager
Joined: 02 Mar 2018
Posts: 69
Location: India
GMAT 1: 640 Q51 V26
GPA: 3.1
A rectangular park which is 20 feet long and 24 feet wide is to be  [#permalink]

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Updated on: 05 Aug 2018, 09:53
00:00

Difficulty:

35% (medium)

Question Stats:

67% (01:41) correct 33% (01:21) wrong based on 27 sessions

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A rectangular park which is 20 feet long and 24 feet wide is to be filled with sand so that the floor of the rectangular park rises by 2 feet. If 1200 cubic feet of sand is available for this purpose, by what percentage is it greater than the actual sand which is required?

A) 50%
B) 20%
C) 10%
D) 40%
E) 25%

Originally posted by gsingh0711 on 05 Aug 2018, 08:36.
Last edited by generis on 05 Aug 2018, 09:53, edited 3 times in total.
Formatted the question
Manager
Joined: 02 Mar 2018
Posts: 69
Location: India
GMAT 1: 640 Q51 V26
GPA: 3.1
Re: A rectangular park which is 20 feet long and 24 feet wide is to be  [#permalink]

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05 Aug 2018, 08:37
Explanation:

A rectangular park (20 feet long and 24 feet wide) is filled with sand, and floor of rectangular park rises by 2 feet.
⇒ Volume of sand required = 20 × 24 × 2 = 960 cubic feet

Sand available = 1200 cubic feet
⇒ Difference between sand required and available sand = 1200 − 960 = 240
⇒ % by which available sand is greater than required sand = (240/960) × 100 = 25%

I think, I deserve a kudus LoL
Senior SC Moderator
Joined: 22 May 2016
Posts: 2200
A rectangular park which is 20 feet long and 24 feet wide is to be  [#permalink]

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05 Aug 2018, 10:29
gsingh0711 wrote:
A rectangular park which is 20 feet long and 24 feet wide is to be filled with sand so that the floor of the rectangular park rises by 2 feet. If 1200 cubic feet of sand is available for this purpose, by what percentage is IT greater than the actual sand which is required?

A) 50%
B) 20%
C) 10%
D) 40%
E) 25%

The hitch in this question is translating the highlighted portion. "IT" = the available 1,200 cubic feet of sand

(1) Volumes of sand: actually needed vs. available
The floor of flat rectangular park rises 2 feet -- in other words, the flat rectangle becomes a rectangular box

Actual volume of sand needed = Volume of the rectangular box, $$V=l*w*h$$
$$l=24$$ feet
$$w=20$$ feet
$$h=2$$ feet

Actually needed volume of sand: $$20*24*2=960$$ cu ft

Available volume of sand: $$1,200$$ cu ft

(2) Percent greater than?
By what percentage is AVAILABLE sand ("it") greater than volume of actual sand needed?

(Available) $$1,200$$ is what percent greater than (actually needed) $$960$$?

Percent greater than = Percent change*
Percent change: $$\frac{New-Old}{Old}*100$$

$$\frac{1,200-960}{960}=\frac{240}{960}=\frac{1}{4}=(0.25*100)$$

$$=25$$ percent

Alternatively, percent greater than: $$(\frac{NewValue}{OldValue}-1)=$$ decimal % greater than
Subtract 1 to account for 100% of old value

$$\frac{1,200}{960}=1.25$$, and $$(1.25-1)=0.25$$

1,200 is 25 percent greater than 960

"Old" = "Original." Another way to write the formula is $$\frac{Change}{Original}*100$$. Almost always, the value after the word "than" is the Old/Original number.
A rectangular park which is 20 feet long and 24 feet wide is to be &nbs [#permalink] 05 Aug 2018, 10:29
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