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22 Jan 2020, 01:46
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Difficulty:
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74% (01:36) correct
26%
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A rectangular park which is 20 feet long and 24 feet wide is to be filled with sand so that the floor of the rectangular park rises by 2 feet. If 1200 cubic feet of sand is available for this purpose, by what percentage is it greater than the actual sand which is required?
A. 50%
B. 40%
C. 25%
D. 20%
E. 10%
22 Jan 2020, 01:58
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Quote:
A rectangular park which is 20 feet long and 24 feet wide is to be filled with sand so that the floor of the rectangular park rises by 2 feet. If 1200 cubic feet of sand is available for this purpose, by what percentage is it greater than the actual sand which is required?
A. 50%
B. 40%
C. 25%
D. 20%
E. 10%
A. 50%
B. 40%
C. 25%
D. 20%
E. 10%
L = 20, B = 24, H (to be increased) = 2
Volume of Sand Needed = L*B*H = 20*24*2 = 960 Cubic feet
Question: 1200 is what percentage greater than 960
i.e. Required output = (1200-960)*100/960 = 25%
ANswer: Option C
22 Jan 2020, 02:20
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Given: Volume of sand available - \(1200 f^3\) .. \(L=20, B=24, H=2\)
Volume required to fill 2 feet - \(20*24*2 = 960 f^3\) \((L*B*H)\)
Extra: Sand available - Sand required .. \(1200-960 = 240\)
So, the percentage of extra: \(\frac{Extra*100 }{ Required}\) ... \(\frac{240 * 100 }{ 960}= 25\)%
'C' is the Winner
Volume required to fill 2 feet - \(20*24*2 = 960 f^3\) \((L*B*H)\)
Extra: Sand available - Sand required .. \(1200-960 = 240\)
So, the percentage of extra: \(\frac{Extra*100 }{ Required}\) ... \(\frac{240 * 100 }{ 960}= 25\)%
'C' is the Winner
