A rectangular region has a fence along three sides and a wall along the fourth side. The fenced side opposite the wall is twice the length of each of the other two fenced sides. If the area of the rectangular region is 128 square feet, what is the total length of the fence, in feet?

A. 4 B. 8 C. 16 D. 32 E. 64
two sides EACH = x the third = 2x and the wall length is thus 2x too

x*2x = 2x^2 = 128 ie x^2 = 64 ie x = 8

L = 16 W=8

TOTAL LENGHT OF FENCE = 2*8+16 = 32

MY ANSWER IS D

32

2x * x = 128
2x^2 = 128
x^2 = 64
x = 8

perimeter = 2x + x + x = 4x = 4(8) = 32

x = 2y
x * y = 128
2y^2 = 128
y = 8
x = 16

fence = y + y + x = 32
D

A rectangular region has a fence along three sides and a wall along the fourth side. The fenced side opposite the wall is twice the length of each of the other two fenced sides. If the area of the rectangular region is 128 square feet, what is the total length of the fence, in feet?
A. 4
B. 8
C. 16
D. 32
E. 64

The fenced side opposite the wall = 2x.
Each of the other two fenced sides = x.

The area = 2x*x=128 --> x=8.

The total length of the fence = x + x + 2x = 4x = 32 feet.

Answer: D.

Hope it's clear.
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Please refer the screenshot attached:

2x ^ 2 = 128
x = 8

4x = Perimeter of fence = 32 (Answer = D)

Rectangular with side a, b, longer side a, shorter side b.
The fenced side opposite the wall is twice the length of each of the other two fenced sides
=> Interpret it as a =2b.
a= 2b, axb = 128 ==> 2b^2 =128 ==> b =8.
=> Total length of the fence = a+2b = 2b+2b = 4b = 8x4 =32.