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[#permalink]
x = 2y
x * y = 128
2y^2 = 128
y = 8
x = 16

fence = y + y + x = 32
D
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A rectangular region has a fence along three sides and a [#permalink]
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A rectangular region has a fence along three sides and a wall along the fourth side. The fenced side opposite the wall is twice the length of each of the other two fenced sides. If the area of the rectangular region is 128 square feet, what is the total length of the fence, in feet?
A. 4
B. 8
C. 16
D. 32
E. 64

The fenced side opposite the wall = 2x.
Each of the other two fenced sides = x.

The area = 2x*x=128 --> x=8.

The total length of the fence = x + x + 2x = 4x = 32 feet.

Answer: D.

Hope it's clear.
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Re: A rectangular region has a fence along three sides and a [#permalink]
Please refer the screenshot attached:

2x ^ 2 = 128
x = 8

4x = Perimeter of fence = 32 (Answer = D)
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wall.JPG
wall.JPG [ 5.57 KiB | Viewed 13608 times ]

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Re: A rectangular region has a fence along three sides and a [#permalink]
Rectangular with side a, b, longer side a, shorter side b.
The fenced side opposite the wall is twice the length of each of the other two fenced sides
=> Interpret it as a =2b.
a= 2b, axb = 128 ==> 2b^2 =128 ==> b =8.
=> Total length of the fence = a+2b = 2b+2b = 4b = 8x4 =32.
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Re: A rectangular region has a fence along three sides and a [#permalink]
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