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1. Per Capita spending = Total amount of money spent/Total population
But here all we know is the percent of people from a particular age group who spent money to go to a particular event. Hence, the given statement cannot be properly inferred.

2. Average age = Weighted average of each age group/ total population.
But here all we know is the percent of people from a particular age group who spent money to go to a particular event.
We do not know the number of people in each age group .So, we cannot infer the given statement.

Third part is not clear to me Sajjad1994 BottomJee pls help
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How can we assume there are only 100 people , there can be 1000 people in the city.

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Sans8

Third part is not clear to me Sajjad1994 BottomJee pls help
Hi Sans8
I am not an expert but here is how I will try to deduce the last statement:
"At least 45% of Federland citizens under the age of 25 attended both a sporting event and a gallery or museum in 2015."

Let's assume there are 100 people within the 0- 25 age group,
No. of citizens who attended Galleries/ Museums, \(M_1\) = 70 (Given in the table)
No. of citizens who didn't attend Galleries/ Museums, \(M_2\) = 100 - 70 = 30

No. of citizens who attended Sporting events, \(S_1\) = 75 (Given in the table)
No. of citizens who didn't attend Sporting events, \(S_2\) = 100 - 75 = 25

There can be different cases of consideration, but let's take the extreme one i.e. "No one from \(M_2\) is in \(S_2\) and vice versa"
Therefore, no. of people who didn't attend both Galleries/ Museums and Sporting events = \(M_2\) + \(S_2\) = 30 + 25 = 55
So, no. of people who attended both events = 100 - 55 = 45

Hence, even in the extreme case, 45 citizens attended both a sporting event and a gallery or museum. (Can be reasonably inferred)
­
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Harsh07112001
How can we assume there are only 100 people , there can be 1000 people in the city.

BottomJee

Sans8

Third part is not clear to me Sajjad1994 BottomJee pls help
Hi Sans8
I am not an expert but here is how I will try to deduce the last statement:
"At least 45% of Federland citizens under the age of 25 attended both a sporting event and a gallery or museum in 2015."

Let's assume there are 100 people within the 0- 25 age group,
No. of citizens who attended Galleries/ Museums, \(M_1\) = 70 (Given in the table)
No. of citizens who didn't attend Galleries/ Museums, \(M_2\) = 100 - 70 = 30

No. of citizens who attended Sporting events, \(S_1\) = 75 (Given in the table)
No. of citizens who didn't attend Sporting events, \(S_2\) = 100 - 75 = 25

There can be different cases of consideration, but let's take the extreme one i.e. "No one from \(M_2\) is in \(S_2\) and vice versa"
Therefore, no. of people who didn't attend both Galleries/ Museums and Sporting events = \(M_2\) + \(S_2\) = 30 + 25 = 55
So, no. of people who attended both events = 100 - 55 = 45

Hence, even in the extreme case, 45 citizens attended both a sporting event and a gallery or museum. (Can be reasonably inferred)
­

We are given percentages, so the actual number of citizens does not matter. You can assume any convenient number and the result will be the same.

In the solution quoted, 100 was chosen simply because it makes the arithmetic easy. For example, 70 percent becomes 70, 75 percent becomes 75, and so on. If you used 1,000 people instead, you would get 700 and 750, but the overlap percentage conclusion would still be identical.

So the use of 100 is not an assumption about population size, it is only a tool for convenience.
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