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# A researcher combined x ounces of a saline solution that contained 20%

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Intern
Joined: 06 Jul 2013
Posts: 43
Location: United States
A researcher combined x ounces of a saline solution that contained 20%  [#permalink]

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01 Jul 2018, 08:37
00:00

Difficulty:

55% (hard)

Question Stats:

59% (00:55) correct 41% (01:05) wrong based on 58 sessions

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A researcher combined x ounces of a saline solution that contained 20 percent saline, by volume, with y ounces of a saline solution that contained 5 percent saline, by volume, to produce z ounces of a saline solution that was 12 percent saline, by volume. What is the value of x?

(1) y = 16
(2) z = 30
Intern
Joined: 06 Jul 2013
Posts: 43
Location: United States
A researcher combined x ounces of a saline solution that contained 20%  [#permalink]

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01 Jul 2018, 17:07
Bump -- could someone please explain why the answer isn't A? This question comes from Jeff Sackman's Word Problem Challenge, btw.
Manager
Joined: 07 Feb 2017
Posts: 179
Re: A researcher combined x ounces of a saline solution that contained 20%  [#permalink]

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01 Jul 2018, 17:30
(.2x+.05y)/z=.12
Z=x+y
(1) (.2x+.8)/(x+16)=.12
(2) (.2x+.05(30-x))/30=.12

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Manager
Joined: 01 Feb 2018
Posts: 64
Location: India
Re: A researcher combined x ounces of a saline solution that contained 20%  [#permalink]

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05 Sep 2018, 23:29
TippingPoint93 wrote:
Bump -- could someone please explain why the answer isn't A? This question comes from Jeff Sackman's Word Problem Challenge, btw.

The first statement is sufficient to get x,

Solving by alligation method,

x y
20 5
12 (z = x+y)
7 8

Hence x and y will be in 7:8 ratio.

Statement 1: y = 16
If y = 16, to maintain the ratio of 7:8, x will have to be 14.
Sufficient.

Statement 2: z=30
z is nothing but x+y,
so x = $$\frac{7}{15}* 30$$
Which is 7*2 = 14.
Sufficient.

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Re: A researcher combined x ounces of a saline solution that contained 20% &nbs [#permalink] 05 Sep 2018, 23:29
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# A researcher combined x ounces of a saline solution that contained 20%

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