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A right circular cone of radius 9 centimetres and height 12

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A right circular cone of radius 9 centimetres and height 12  [#permalink]

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Updated on: 13 Oct 2019, 12:02
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A right circular cone of radius 9 centimetres and height 12 centimetres is cut parallel to the base, to form two pieces such that the height of smaller cone is half the height of frustum. What is the curved surface area of frustum?

A)60π
B)72π
C)90π
D)104π
E)120π

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Originally posted by vishal702992 on 13 Oct 2019, 11:17.
Last edited by vishal702992 on 13 Oct 2019, 12:02, edited 1 time in total.
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Re: A right circular cone of radius 9 centimetres and height 12  [#permalink]

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13 Oct 2019, 11:55
1
curved surface area of frustum= $$pi*L*(r_1+r_2)$$
= pi*10*(3+9)=120*pi

vishal702992 wrote:
A right circular cone of radius 9 centimetres and height 12 centimetres is cut parallel to the base, to form two pieces such that the height of smaller cone is half the height of frustum. What is the curved surface area of frustum ?

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Re: A right circular cone of radius 9 centimetres and height 12  [#permalink]

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13 Oct 2019, 11:58
1
vishal702992 wrote:
A right circular cone of radius 9 centimetres and height 12 centimetres is cut parallel to the base, to form two pieces such that the height of smaller cone is half the height of frustum. What is the curved surface area of frustum ?

Posted from my mobile device

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Re: A right circular cone of radius 9 centimetres and height 12  [#permalink]

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13 Oct 2019, 12:54
The question is discussed before:
https://gmatclub.com/forum/a-right-circ ... l#p2028761
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Re: A right circular cone of radius 9 centimetres and height 12   [#permalink] 13 Oct 2019, 12:54
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