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Difficulty:
65%
(hard)
Question Stats:
58% (01:57) correct
42%
(01:54)
wrong
based on 141
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A rod that weighs 20 pounds is cut into two pieces so that one of the pieces weighs 16 pounds and is 36 feet long. If the weight of each piece is directly proportional to the square of its length, how many feet long is the other piece of rod?
(A) 9
(B) 12
(C) 18
(D) 24
(E) 27
(A) 9
(B) 12
(C) 18
(D) 24
(E) 27
The weight of the other piece is 4 pounds. And we are given that 16/(36^2) = 4/(x^2). (the weight of each piece is directly proportional to the square of its length). We solve for x.
x^2 = ((36^2)*4)/16
x^2 = 36^2/2^2
x = 18 is the answer.
x^2 = ((36^2)*4)/16
x^2 = 36^2/2^2
x = 18 is the answer.
29 Oct 2025, 03:09
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A rod that weighs 20 pounds is cut into two pieces so that one of the pieces weighs 16 pounds and is 36 feet long. If the weight of each piece is directly proportional to the square of its length, how many feet long is the other piece of rod?
Total weight = 20
1 pics =16 other is =4
So, the ratio 4:1
So if one part is 36 long
Then other part is 36/4 = 9
So the answer is 9(A)
Total weight = 20
1 pics =16 other is =4
So, the ratio 4:1
So if one part is 36 long
Then other part is 36/4 = 9
So the answer is 9(A)
