Bunuel wrote:
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
A. $250
B. $500
C. $750
D. $1,000
E. $1,250
Given:
1. A school purchased 2 computers whose prices were $1,000 and $2,000, respectively.
2. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive.
Asked: The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
Greatest average of 4 computers = ($2000*3 + $1000)/4 = $7000/4 = $1750
Least average of 4 computers = ($2000 + 3*$1000)/4 = $5000/4 = $1250
Difference = $1750 - $1250 = $500
IMO B
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Kinshook Chaturvedi
Email: kinshook.chaturvedi@gmail.com