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Math Expert
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Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re [#permalink]
Bunuel wrote:
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?

A. $250
B. $500
C. $750
D. $1,000
E. $1,250


Maximum average=(1000+2000+2000+2000)/4=1750
Minimum average =(1000+2000+1000+1000)/4=1250
So, the difference in the two averages is=1750-1250=500

Thus, the correct answer is option B.
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Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re [#permalink]
1000+2000+2000+2000=7000
1000+2000+1000+1000=5000
(7000/4)-(5000/4)
=2000/4
=500

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Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re [#permalink]
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