Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Does GMAT RC seem like an uphill battle? e-GMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days.
Sign up or for Target Test Prep’s weekly Quant webinar series. The free weekly webinar covers sophisticated, yet easy-to-deploy, tactics and strategies for handling commonly misunderstood, high-value GMAT quant problems.
Enter The Economist GMAT Tutor’s Brightest Minds competition – it’s completely free! All you have to do is take our online GMAT simulation test and put your mind to the test. Are you ready? This competition closes on December 13th.
A school purchased 2 computers whose prices were $1,000 and $2,000, re
[#permalink]
Show Tags
14 Oct 2019, 08:29
00:00
A
B
C
D
E
Difficulty:
25% (medium)
Question Stats:
91% (01:08) correct 9% (01:00) wrong based on 33 sessions
HideShow timer Statistics
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re
[#permalink]
Show Tags
14 Oct 2019, 08:35
Bunuel wrote:
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
A. $250 B. $500 C. $750 D. $1,000 E. $1,250
Given: 1. A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. 2. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive.
Asked: The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
Greatest average of 4 computers = ($2000*3 + $1000)/4 = $7000/4 = $1750
Least average of 4 computers = ($2000 + 3*$1000)/4 = $5000/4 = $1250
Difference = $1750 - $1250 = $500
IMO B
_________________
"Success is not final; failure is not fatal: It is the courage to continue that counts."
Please provide kudos if you like my post. Kudos encourage active discussions.
Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re
[#permalink]
Show Tags
14 Oct 2019, 09:29
Bunuel wrote:
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
A. $250 B. $500 C. $750 D. $1,000 E. $1,250
Max Average \(= \frac{1000 + 2000 + 2000 + 2000}{4} = 1750\)
Min Average \(= \frac{1000 + 2000 + 1000 + 1000}{4} = 1250\)
So, the difference is $ 500 , Answer must be (B)
_________________
Thanks and Regards
Abhishek....
PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS
Re: A school purchased 2 computers whose prices were $1,000 and $2,000, re
[#permalink]
Show Tags
14 Oct 2019, 10:08
Bunuel wrote:
A school purchased 2 computers whose prices were $1,000 and $2,000, respectively. The school is to purchase 2 more computers from a list of computers whose prices range from $1,000 to $2,000, inclusive. The greatest possible average (arithmetic mean) price of the 4 computers is how much greater than the least possible average price of the 4 computers?
A. $250 B. $500 C. $750 D. $1,000 E. $1,250
Maximum average=(1000+2000+2000+2000)/4=1750 Minimum average =(1000+2000+1000+1000)/4=1250 So, the difference in the two averages is=1750-1250=500
close
91% (01:08) correct 
