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Re: A sequence of numbers, S1, S2, S3, . . ., is defined by Sk = k2 – k fo [#permalink]
D.

Sk=k^2–k = K(K-1) i.e. Sum of two consecutive integers i.e. (k-1 ) & k

Sn = 110 = 11 * 10. i.e. n =11

n-1 = 10

Sn-1 = 10 * 9 = 90
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Re: A sequence of numbers, S1, S2, S3, . . ., is defined by Sk = k2 – k fo [#permalink]
Bunuel wrote:
A sequence of numbers, \(S_1\), \(S_2\), \(S_3\), ..., is defined by \(S_k = k^2 – k\) for all positive integers k. If the value \(S_n\) is 110, what is the value of \(S_{n – 1}\) ?

A. 132
B. 100
C. 98
D. 90
E. 72


PS21273


\(S_n = 110\)
\(110 = n^2 - n\)
\(110 = n(n-1)\)
\(n = 11\)
\(n - 1 = 10\)

\(10^2 - 10 = 90\)

Answer is D.
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Re: A sequence of numbers, S1, S2, S3, . . ., is defined by Sk = k2 – k fo [#permalink]
Expert Reply

Solution



Given
In this question, we are given that
    • A sequence is defined by the general term \(S_k = k^2 – k\), for all positive integers k
    • The value of \(S_n\) is 110

To find
We need to determine
    • The value of \(S_{n-1}\)

Approach and Working out
As per the given definition,
    • \(S_n = n^2 – n = 110\)
    Or, \(n^2 – n – 110 = 0\)
    Or, \(n^2 – 11n + 10n – 110 = 0\)
    Or, (n – 11) (n + 10) = 0
Hence, n = 11 (as n cannot be negative)

Therefore, \(S_{n-1}\) = \(S_{10}\) = \(10^2 – 10\) = 100 – 10 = 90

Thus, option D is the correct answer.

Correct Answer: Option D
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Re: A sequence of numbers, S1, S2, S3, . . ., is defined by Sk = k2 k fo [#permalink]
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Re: A sequence of numbers, S1, S2, S3, . . ., is defined by Sk = k2 k fo [#permalink]
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