Bunuel
A set is such that if m is in the set, (m + 3) is also in the set. If −3 is in the set, which of the following is also in the set?
I. −6
II. 0
III. 6
(A) Only I
(B) Only II
(C) Only I and II
(D) Only II and III
(E) I, II and III
As we are explicitly given a rule to follow, we'll follow it.
This is a Precise approach
If -3 is in the set, (-3)+3 = 0 is in the set. So II is true.
Since 0 is in the set, 0+3 = 3 is in the set and since 3 is in the set, 3 +3 = 6 is in the set.
So III is also true. We do not have information about numbers smaller than -3 and cannot conclude if I is true or not.
(D) is our answer.
Note that a different, Logical approach would have been to recognize that what we are doing is creating a set out of an arithmetic sequence with a difference of 3. Since one of the elements is -3, a multiple of 3, then the set contains all multiples of 3 starting from some number. The first number has to be at least -3 so II and III are true but we do not know if the first number in the set is smaller/equal to -6 or not so cannot conclude if I is true.