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04 Oct 2018, 00:24
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:34) correct
36%
(01:33)
wrong
based on 329
sessions
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A set of 13 different integers has a median of 20 and a range of 20. What is the greatest possible value of the integer in the set?
(A) 23
(B) 27
(C) 30
(D) 34
(E) 40
(A) 23
(B) 27
(C) 30
(D) 34
(E) 40
Updated on: 04 Oct 2018, 06:08
Originally posted by GMATinsight on 04 Oct 2018, 00:40.
Last edited by GMATinsight on 04 Oct 2018, 06:08, edited 1 time in total.
Last edited by GMATinsight on 04 Oct 2018, 06:08, edited 1 time in total.
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Bunuel
Median of 13 different integers = 7th Term = 20
Range = Highest - Lowest = 20
Sets is { -, -, -, -, -, -, 20, -, -, -, -, -, -)
For Highest value of largest value of set, th elowest value also should be maximized because their difference is constant which is 20 in this case
To maximize the lowest value we can start going backward from median value keeping every previous value highest
Highest value of the 6th term which must be less than 20 is = 19
Highest value of the 5th term which must be less than 19 is = 18
Highest value of the 4th term which must be less than 18 is = 17
Highest value of the 3rd term which must be less than 17 is = 16
Highest value of the 2nd term which must be less than 16 is = 15
Highest value of the 1st term which must be less than 15 is = 14
Lowest value is 14 i.e. highest value = 20+14 = 34
Answer: Option D
04 Oct 2018, 05:23
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GMATinsight
How does the 7th Term become 13?
Im sorry but im having a really hard time understanding answers posted by you on other questions as well. I would like to request to give a detailed analysis. Thanks in advance.
