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# A side of beef lost 35 percent of its weight in processing. If the

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A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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23 Nov 2015, 13:13
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15% (low)

Question Stats:

89% (01:29) correct 11% (01:23) wrong based on 59 sessions

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A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 546 pounds after processing, how many pounds did it weigh before processing?

(A) 191
(B) 355
(C) 737
(D) 840
(E) 1,560

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Re: A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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23 Nov 2015, 19:33
Let weight of side of beef before processing = x
(65/100)*x = 546
=> x = (546 * 100)/65 = 840

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Re: A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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25 Nov 2015, 10:42
Hi All,

Since this prompt asks for the weight of the meat BEFORE it lost 35% of its weight, and the answer choices are numbers, we can TEST THE ANSWERS.

We're told that the 'after'-weight is 546 pounds, so the 'before'-weight clearly has to be higher than that. Considering the 35% drop in weight, the likely Answer is either C or D, so we'll start with one of those...

10% of 840 = 84 pounds
35% of 840 = 3.5(84) = 294 pounds

840 - 294 = 546 pounds

This is an exact MATCH for what we were told, so this MUST be the answer.

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Re: A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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25 Nov 2015, 12:14
Bunuel wrote:
A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 546 pounds after processing, how many pounds did it weigh before processing?

(A) 191
(B) 355
(C) 737
(D) 840
(E) 1,560

Let the weight of the beef before processing be 100 after processing , weight of the beef is 65

When the weight of the beef is 65 (after processing) ; weight of the beef before processing is 100

When the weight of the beef is 1 (after processing) ; weight of the beef before processing is 100/65

When the weight of the beef is 540 (after processing) ; weight of the beef before processing is (100/65)*540 => 840

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Re: A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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29 Aug 2016, 03:08
let the weight of the side of beef before processing be x pounds
it lost 35 % of its weight during processing so now the weight is .65x
but .65x = 546 pounds
so weight of side of beef before processing is x = 840 pounds
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Re: A side of beef lost 35 percent of its weight in processing. If the  [#permalink]

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21 Mar 2018, 16:18
Bunuel wrote:
A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 546 pounds after processing, how many pounds did it weigh before processing?

(A) 191
(B) 355
(C) 737
(D) 840
(E) 1,560

We can create the equation where n = the weight of the beef before processing:

0.65n = 546

n = 546/0.65 = 840

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Re: A side of beef lost 35 percent of its weight in processing. If the   [#permalink] 21 Mar 2018, 16:18
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