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Bunuel
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one layered = $40
2 layered = $75

total cost=13900

Option 1:
No. of 2 layered cake be x
Then 1 layered cake 2x-40

x*75+(2x-40)*40=13900

solvable for X hence should be sufficient.

Option 2:
2 layered =x
1 layered x-60

Following same eq x*75+40(x-60)=13900
Solvable again and sufficient . Hence option Should be D
Bunuel
A specialty bakery sells decorated onelayer cakes for $40 and two-layer decorated cakes for $75. If last month the bakery’s total sales for decorated onelayer and two-layer cakes was $13,900, how many decorated one-layer and twolayer cakes did the bakery sell last month?

(1) Last month, the number of decorated one-layer cakes sold was 40 less than twice the number of decorated twolayer cakes sold.
(2) Last month, the number of decorated two-layer cakes sold was 60 less than the number of decorated one-layer cakes sold.


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In my opinion, such questions are the low-hanging fruits, essentially doesn't need to be even solved to find an exact answer:upsidedown

The question stem gives an equation in two variables.

Out job is to find whether:
  • A relation is provided between these two variables so that we have two equations and two unknown variables
  • Either one of the variables is given, this will give us one equation and one unknown variables

In both these cases stated above, we can have an answer for missing variables

Statement 1: Provided a relation
Statement 2: Provided a relation

Answer D
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A specialty bakery sells decorated onelayer cakes for $40 and two-layer decorated cakes for $75. If last month the bakery’s total sales for decorated onelayer and two-layer cakes was $13,900, how many decorated one-layer and twolayer cakes did the bakery sell last month?
40A+75B=13,900 .....(1)
A+B=?

(1) Last month, the number of decorated one-layer cakes sold was 40 less than twice the number of decorated twolayer cakes sold.
A=2B-40
Put value of A in (1)
40(2B-40)+75B=13,900
80B+75B-1600=13,900
155B=15,500
B=100
A=200-40=160
A+B=160+100=260
Sufficient

(2) Last month, the number of decorated two-layer cakes sold was 60 less than the number of decorated one-layer cakes sold.
B=A-60
Solve with (1)
40A+75(A-60)=13,900
40A+75A-4500=13900
115A=13900+4500=18400
A=18400/115=160
B=160-60=100
Sufficient

D
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