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05 Oct 2018, 22:42
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:40) correct
29%
(02:30)
wrong
based on 72
sessions
History
Date
Time
Result
Not Attempted Yet
A square with a side of 5 is positioned with its Corner in the center of a square with a side of 4, as shown. One side of the overlapping region is equal to 3. What is the area Of overlap between the two squares (the area of the red shape)?
(A) \(\frac{3}{(\sqrt{2})}\)
(B) 2
(C) 4
(D) \(\frac{6}{(\sqrt{3})}\)
(E) 5
Attachment:
GC.jpg [ 13.41 KiB | Viewed 8008 times ]
05 Oct 2018, 23:10
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IMO C.
I did not use the big square in my calculation.If you divide the square with side 4 into halves vertically as well as horizontally each side of the 4 smaller square formed will be 2. From there we can proceed further.
Let me know if my answer is correct. I will share the diagrammatic representation of my solution.
I did not use the big square in my calculation.If you divide the square with side 4 into halves vertically as well as horizontally each side of the 4 smaller square formed will be 2. From there we can proceed further.
Let me know if my answer is correct. I will share the diagrammatic representation of my solution.
05 Oct 2018, 23:12
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OA = C, provide your explanation
warrior1991
