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15 Feb 2025, 18:25
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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A test had \(180\) questions. Each correct answer carried \(2\) marks. Each wrong answer carried \(-\frac{1}{2}\) mark, and unanswered questions carried no mark.
Alex attempted all the questions in the test and scored \(320\) marks.
What would his marks be if for each correct answer he got only \(\frac{1}{2}\) mark and for each wrong answer he lost \(2\) marks?
(A) 40
(B) 50
(C) 60
(D) 80
Alex attempted all the questions in the test and scored \(320\) marks.
What would his marks be if for each correct answer he got only \(\frac{1}{2}\) mark and for each wrong answer he lost \(2\) marks?
(A) 40
(B) 50
(C) 60
(D) 80
06 Apr 2025, 10:18
Kudos
Bookmarks
Number of correct answers= x
Number of wrong answers= y
x+y=180 .......(1)
2(x)-(1/2)y=320........(2)
4x-y=640
4x-(180-x)=640
5x=640+180=820
x=820/5=164 And y=180-164=16
If for each correct answer he gets 1/2 mark and for wrong answers (-2), then his marks would be
= (1/2)164+(-2)(16)
=82-32=50
Answer: B
Number of wrong answers= y
x+y=180 .......(1)
2(x)-(1/2)y=320........(2)
4x-y=640
4x-(180-x)=640
5x=640+180=820
x=820/5=164 And y=180-164=16
If for each correct answer he gets 1/2 mark and for wrong answers (-2), then his marks would be
= (1/2)164+(-2)(16)
=82-32=50
Answer: B
06 Apr 2025, 11:06
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supremekai
A test had \(180\) questions. Each correct answer carried \(2\) marks. Each wrong answer carried \(-\frac{1}{2}\) mark, and unanswered questions carried no mark.
Alex attempted all the questions in the test and scored \(320\) marks.
What would his marks be if for each correct answer he got only \(\frac{1}{2}\) mark and for each wrong answer he lost \(2\) marks?
(A) 40
(B) 50
(C) 60
(D) 80
Let x be the number of questions that’s correct. And, 180-x be the number of questions which is wrong. Alex attempted all the questions in the test and scored \(320\) marks.
What would his marks be if for each correct answer he got only \(\frac{1}{2}\) mark and for each wrong answer he lost \(2\) marks?
(A) 40
(B) 50
(C) 60
(D) 80
Case 1: correct answer = 2 marks, incorrect answers = -1/2
2x + (180-x)*(-1/2) =320
2x -90 +x/2 =320
5x/2 =410
x = 164 . Number of correct questions = 164
Wrong question = 180 -164 =16
Case 1: correct answer = 1/2 marks, incorrect answers = -2
164 questions at 1/2 mark gives 82.
16 questions at -2 will give -32.
Total marks = 82-32 = 50
