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Differential Speed= 15 Km/hr =15 *5/18 m/sec

Length = distance travelled at differential speed in 48 sec= 15*5/18*48 m = 200 m

Option A is the correct
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Bunuel
A train running at the rate of 40 km/h passes a man riding parallel to the railway line in the same direction at 25 km/h in 48 sec. Find the length of the train in metres.

(A) 200 m
(B) 150 m
(C) 100 m
(D) 50 m
(E) 10 m
Solution:

We will solve in kilometers and hours and then convert kilometers to meters. Since 1 hour = 3,600 seconds, then 48 seconds is 48/3600 = 1/75 hours.

Since time = (total distance) / (relative speed in same direction), we can let length of the train be L and create the equation:

1/75 = (L + 0)/(40 - 25)

1/75 = L/15

75L = 15

L = 15/75 = 1/5

We see that the length of the train is 1/5 km or 1/5 x 1000 = 200 m.

Answer: A
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