Bunuel wrote:

A truck driver drove for two days. On the second day she drove 2 hours less and at an average speed 5 miles per hour faster than she drove on the first day. If during the two days she drove a total of 1,245 miles and spent a total of 20 hours driving, what was her average speed on the first day?

A. 55 mph

B. 58 mph

C. 60 mph

D. 62 mph

E. 65 mph

Let x = average speed Day 1

x + 5 = average speed Day 2

Solve for time, then distance.

Total time 20 hours, 2 hrs less on Day 2 = (t-2)

t + t - 2 = 20

2t = 22

t = 11: Day 1

t - 2 = 9: Day 2

Distance, rt = D

Day 1: x * 11 = (11x)

Day 2: (x + 5) * 9 = (9x + 45)

Day1 + Day 2 = total distance

11x + 9x + 45 = 1,245

20x = 1,200

x = 60

Average speed Day 1 = 60

Answer C

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that within me there lay an invincible summer.

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