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the first truck has traveled one more hour than the second at the time two trucks pass each other

­\(\frac{x}{50} - 1 = \frac{490 - x}{60}\)­

­\(x = 250\)­
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I understood the solution. But I have a doubt in this.
The question doesn't say that the trucks are travelling at the constant speed.
Infact, question mentions the AVERAGE speed till the time trucks pass each other.

In this case, is it correct to assume that Truck 1 covered 50 miles in first hour of its journey?­
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A truck left City M and traveled toward City N. A second truck left City N exactly 1 hour later and traveled toward City M. The trucks passed each other after they had traveled, nonstop, a combined total of 490 miles. If the average speeds of the trucks up to the time they passed each other were 50 miles per hour (mph) and 60 mph, respectively, how far, to the nearest mile, had the first truck traveled when the trucks passed each other?

A. 223
B. 240
C. 245
D. 250
E. 300

I understood the solution. But I have a doubt in this.
The question doesn't say that the trucks are travelling at the constant speed.
Infact, question mentions the AVERAGE speed till the time trucks pass each other.

In this case, is it correct to assume that Truck 1 covered 50 miles in first hour of its journey?­
­
No, assuming that the truck from City M covered 50 miles in the first hour isn't necessarily correct. The question specifies the average speed, not the constant speed. However, you can set up the equation 50t + 60(t - 1) = 490 without needing to split the distances covered in the first hour and the rest of the time. Having said that, in this particular question, assuming a constant speed would still yield the correct result.
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Since in this question, we can take average speed to be equal to constant speed, here is how I did it.

In the first hour, first truck will travel 50 miles.
Total miles remaining = 490 - 50 = 440

Combined speed = 110

Time travelled = 440/110 = 4 hours.

First truck has travelled for 4 + 1 = 5 hours.

Distance travelled = 50*5 = 250 miles.
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I assumed the distance traveled by the first truck was x. Since the first truck had traveled for 1 hour longer than the second, I set up the equation as:
x/50 - x/60 = 1

Solving this gave me x = 300. Is it because this approach works only when 2 distances are equal?
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A truck left City M and traveled toward City N. A second truck left City N exactly 1 hour later and traveled toward City M. The trucks passed each other after they had traveled, nonstop, a combined total of 490 miles. If the average speeds of the trucks up to the time they passed each other were 50 miles per hour (mph) and 60 mph, respectively, how far, to the nearest mile, had the first truck traveled when the trucks passed each other?

A. 223
B. 240
C. 245
D. 250
E. 300

I understood the solution. But I have a doubt in this.
The question doesn't say that the trucks are travelling at the constant speed.
Infact, question mentions the AVERAGE speed till the time trucks pass each other.

In this case, is it correct to assume that Truck 1 covered 50 miles in first hour of its journey?­
­
No, assuming that the truck from City M covered 50 miles in the first hour isn't necessarily correct. The question specifies the average speed, not the constant speed. However, you can set up the equation 50t + 60(t - 1) = 490 without needing to split the distances covered in the first hour and the rest of the time. Having said that, in this particular question, assuming a constant speed would still yield the correct result.

I assumed the distance traveled by the first truck was x. Since the first truck had traveled for 1 hour longer than the second, I set up the equation as:
x/50 - x/60 = 1

Solving this gave me x = 300. Is it because this approach works only when 2 distances are equal?

Yes, it's because that approach only works when the distances are equal, which they aren’t in this case. The trucks travel different distances.
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