Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 2106:30 AM PDT
-08:30 AM PDT
Not only the typical inference questions but also all other CR questions on the GMAT require the ability to deduce from the given information. Come master how to draw inferences accurately and efficiently with Verbal Expert-Sunita Singhvi. Limited Seats!
Jun 2111:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
Jun 2211:30 AM EDT
-12:30 PM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Jun 2308:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jun 3008:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates!
13 Jan 2014, 13:07
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
60% (03:19) correct
40%
(03:15)
wrong
based on 445
sessions
History
Date
Time
Result
Not Attempted Yet
A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.?
15 minutes
25 minutes
1 hour 15 minutes
1 hour 40 minutes
4 hours 30 minutes
OE
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
15 minutes
25 minutes
1 hour 15 minutes
1 hour 40 minutes
4 hours 30 minutes
OE
Trains coming from X arrive at Y at 45 minutes past the hour.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
02 Mar 2015, 02:28
Kudos
Bookmarks
goodyear2013
A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.?
15 minutes
25 minutes
1 hour 15 minutes
1 hour 40 minutes
4 hours 30 minutes
OE
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
15 minutes
25 minutes
1 hour 15 minutes
1 hour 40 minutes
4 hours 30 minutes
OE
Trains coming from X arrive at Y at 45 minutes past the hour.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
Make a departure arrival diagram to minimize the waiting time.
Attachment:
FullSizeRender.jpg [ 1.49 MiB | Viewed 12456 times ]
Trains depart from Y at 9/9:30/10/10:30 etc. This means a minimum wait of 15 mins is required at Y.
They arrive at Z at 11:20/11:50/12:20/12:50. They depart from Z at 8/8:45/9:30/10:15/11/11:45/12:30 and so on. Note that if she arrives at Z at 20 mins past the hour, she will need to wait for at least 10 mins for 12:30/3:30 etc train. If she arrives at 50 mins past the hour, again she needs to wait for at least 10 mins to take the 2 o clock train. So anyway 10 mins at Z is a given.
So minimum she will need to wait for 15+10 = 25 mins.
This works out if she takes 8 o clock train from X, reaches Y at 9:45, takes 10 o clock train from Y and reaches Z at 12:20 and takes 12:30 train from Z.
Answer (B)
19 Jun 2015, 07:16
Kudos
Bookmarks
I would prefer back solving for this question.
Reached Z @ 3:30 PM, from Y-->Z it will take 140 minutes, so she should have started from Y @ 1:10 PM but trains from Y to Z leaves at every 30mins starting at 9am,therefore she should board into the train @1PM and wait at station Z for 10minutes for her next train from station Z.
Now, X --> Y journey:
To reach Y at 1PM she should start from X by 11AM atleast as, journey time is 105minutes .If she will start from station X by 11AM then she will reach Y by 12:45 PM, hence will wait for 15minutes before she board into 1PM train from station Y.
Total waiting time= 15+10=25 minutes.
Hope that was helpful.
Cheers,
Gaurav
Reached Z @ 3:30 PM, from Y-->Z it will take 140 minutes, so she should have started from Y @ 1:10 PM but trains from Y to Z leaves at every 30mins starting at 9am,therefore she should board into the train @1PM and wait at station Z for 10minutes for her next train from station Z.
Now, X --> Y journey:
To reach Y at 1PM she should start from X by 11AM atleast as, journey time is 105minutes .If she will start from station X by 11AM then she will reach Y by 12:45 PM, hence will wait for 15minutes before she board into 1PM train from station Y.
Total waiting time= 15+10=25 minutes.
Hope that was helpful.
Cheers,
Gaurav
