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A woman is planning a trip that involves 3 connecting trains
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13 Jan 2014, 13:07
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63% (03:31) correct 37% (03:09) wrong based on 221 sessions
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A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.? 15 minutes 25 minutes 1 hour 15 minutes 1 hour 40 minutes 4 hours 30 minutes OE Trains coming from X arrive at Y at 45 minutes past the hour. Trains leave Y on the hour and the halfhour. So minimum wait at Y will be 0:15. This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:2012:30) and as long as 40 minutes (11:5012:30).
For shortest total waiting time possible, need to combine a 15minute wait for the second train with a 10minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z. Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
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Re: A woman is planning a trip that involves 3 connecting trains
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02 Mar 2015, 02:28
goodyear2013 wrote: A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.? 15 minutes 25 minutes 1 hour 15 minutes 1 hour 40 minutes 4 hours 30 minutes OE Trains coming from X arrive at Y at 45 minutes past the hour. Trains leave Y on the hour and the halfhour. So minimum wait at Y will be 0:15. This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:2012:30) and as long as 40 minutes (11:5012:30).
For shortest total waiting time possible, need to combine a 15minute wait for the second train with a 10minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z. Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please. Make a departure arrival diagram to minimize the waiting time. Attachment:
FullSizeRender.jpg [ 1.49 MiB  Viewed 3187 times ]
Trains depart from X at 6/7/8/9 and reach Y at 7:45/8:45/9:45 etc Trains depart from Y at 9/9:30/10/10:30 etc. This means a minimum wait of 15 mins is required at Y. They arrive at Z at 11:20/11:50/12:20/12:50. They depart from Z at 8/8:45/9:30/10:15/11/11:45/12:30 and so on. Note that if she arrives at Z at 20 mins past the hour, she will need to wait for at least 10 mins for 12:30/3:30 etc train. If she arrives at 50 mins past the hour, again she needs to wait for at least 10 mins to take the 2 o clock train. So anyway 10 mins at Z is a given. So minimum she will need to wait for 15+10 = 25 mins. This works out if she takes 8 o clock train from X, reaches Y at 9:45, takes 10 o clock train from Y and reaches Z at 12:20 and takes 12:30 train from Z. Answer (B)
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Re: A woman is planning a trip that involves 3 connecting trains
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13 Jan 2014, 13:15
goodyear2013 wrote: A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.? 15 minutes 25 minutes 1 hour 15 minutes 1 hour 40 minutes 4 hours 30 minutes OE Trains coming from X arrive at Y at 45 minutes past the hour. Trains leave Y on the hour and the halfhour. So minimum wait at Y will be 0:15. This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:2012:30) and as long as 40 minutes (11:5012:30).
For shortest total waiting time possible, need to combine a 15minute wait for the second train with a 10minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z. Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please. This is a reworded OG question: anairlinepassengerisplanningatripthatinvolvesthree108830.html
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A woman is planning a trip that involves 3 connecting trains
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19 Jun 2015, 07:16
I would prefer back solving for this question. Reached Z @ 3:30 PM, from Y>Z it will take 140 minutes, so she should have started from Y @ 1:10 PM but trains from Y to Z leaves at every 30mins starting at 9am,therefore she should board into the train @1PM and wait at station Z for 10minutes for her next train from station Z. Now, X > Y journey:To reach Y at 1PM she should start from X by 11AM atleast as, journey time is 105minutes .If she will start from station X by 11AM then she will reach Y by 12:45 PM, hence will wait for 15minutes before she board into 1PM train from station Y. Total waiting time= 15+10=25 minutes. Hope that was helpful. Cheers, Gaurav



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Re: A woman is planning a trip that involves 3 connecting trains
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13 Jan 2016, 19:36
kind of tricky one...but as bunuel said..looks like an og question... if passenger leaves at 8AM, then arrives at Y at 9:45AM, departs at 10AM, or waits 15 minutes (always 15 mins, since the timing is always 15 mins either behind or late) trains at Z depart at 8:45, 9:30, 10:15, 11:00, 11:45, 12:30, 1:15PM, 2PM, 2:45PM 8:45, 9:30, 10:15, and 11:00 can't be, so right away out. note that the train from Y to Z alone takes 2h20min, and train Y starts at 9AM. if starts at 9AM, then it will arrive at Z at 11:20, which makes 25 mins wait time at Z. if starts at 9:30 > arrives at 11:50  wait time  40 minutes. nope if starts at 10 > arrives at 12:20  wait time 10 minutes. if starts at 10:30 > arrives at 12:50 > wait time 25 minutes if starts at 11 > arrives at 1:20PM, wait time 40 minutes. if starts at 11:30 > arrives at 1:50 > wait time 10 minutes. if starts at 12 > arrives at 12:20 > wait time 25 mins. thus, the min time to wait would be 10 mins at Z. 15+10 = 25 can't be 15, since the time to wait at Y only is 15, and there is no such way that there is no wait time at Z.



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Re: A woman is planning a trip that involves 3 connecting trains
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19 Apr 2018, 16:58
goodyear2013 wrote: A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.? 15 minutes 25 minutes 1 hour 15 minutes 1 hour 40 minutes 4 hours 30 minutes We see that the total wait time is the total time waiting at stations Y and Z assuming that she doesn’t have to wait at station X. Let’s also let the trains leaving at stations X, Y and Z be trains X, Y and Z, respectively. Assuming she arrives at station X exactly on the hour, except for arriving at 6 am at station X, she must wait 15 minutes at station Y for train Y. For example, if she catches train X at station X at 7 am, she will arrive at station Y at 8:45 am and catch train Y at 9 am. If she catches train X at station X at 8 am, she will arrive at station Y at 9:45 am and catch train Y at 10 am. We see that the minimum wait time at station Y is 15 minutes. Now let’s see how we can minimize the wait time at station Z. Since train Z leaves station Z every 45 minutes beginning at 8 am, train Z leaves station Z at 8 am, 8:45 am, 9:30 am, 10:15 am, 11 am, 11:45 am, 12:30 pm, etc. Also, since train Y takes 2 hours and 20 minutes to arrive at station Z and it leaves station Y every 30 minutes beginning at 9 am, train Y will arrive at station Z at 11:20 am, 11:50 am, 12:20 pm, etc. We see that the minimum wait time is 10 minutes if she can arrive at station Z at 12:20 pm and take train Z at 12:30 pm. Thus the minimum total wait time is 15 + 10 = 25 minutes. Answer: B
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