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# A worker places a rectangular electrical box so that it is entirely co

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Math Expert
Joined: 02 Sep 2009
Posts: 48117
A worker places a rectangular electrical box so that it is entirely co  [#permalink]

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04 Dec 2017, 22:58
00:00

Difficulty:

25% (medium)

Question Stats:

79% (01:28) correct 21% (01:52) wrong based on 19 sessions

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A worker places a rectangular electrical box so that it is entirely contained in a rectangular hole 8 feet long, 6 feet wide, and 3 feet deep. If the box fills 20 percent of the hole, and is 6 feet long and 4 feet wide, how many feet is the other dimension of the box?

(A) 0.7
(B) 1.2
(C) 1.8
(D) 2.0
(E) 2.4

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Re: A worker places a rectangular electrical box so that it is entirely co  [#permalink]

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04 Dec 2017, 23:02
Bunuel wrote:
A worker places a rectangular electrical box so that it is entirely contained in a rectangular hole 8 feet long, 6 feet wide, and 3 feet deep. If the box fills 20 percent of the hole, and is 6 feet long and 4 feet wide, how many feet is the other dimension of the box?

(A) 0.7
(B) 1.2
(C) 1.8
(D) 2.0
(E) 2.4

8 * 6 * 3 * 0.2 = 6 * 4 * x
x= 1.2
B
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A worker places a rectangular electrical box so that it is entirely co  [#permalink]

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04 Dec 2017, 23:05
Bunuel wrote:
A worker places a rectangular electrical box so that it is entirely contained in a rectangular hole 8 feet long, 6 feet wide, and 3 feet deep. If the box fills 20 percent of the hole, and is 6 feet long and 4 feet wide, how many feet is the other dimension of the box?

(A) 0.7
(B) 1.2
(C) 1.8
(D) 2.0
(E) 2.4

I try B.

- Volume of rectangular hole = $$8*6*3$$ = 144 feet$$^3$$
- The box is placed 20% of that hole, means the box is placed 144 feet$$^3$$*20% = 28,8 feet$$^3$$
- So, volume box = $$28,8 feet^3 / (6*4)$$ = 1.2 feet.

B. Wdyt?
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A worker places a rectangular electrical box so that it is entirely co  [#permalink]

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05 Dec 2017, 09:39
Bunuel wrote:
A worker places a rectangular electrical box so that it is entirely contained in a rectangular hole 8 feet long, 6 feet wide, and 3 feet deep. If the box fills 20 percent of the hole, and is 6 feet long and 4 feet wide, how many feet is the other dimension of the box?

(A) 0.7
(B) 1.2
(C) 1.8
(D) 2.0
(E) 2.4

The box's volume (6 * 4 * x) is 20 percent of the hole's volume (8 * 6 * 3):

[size=90]$$6 * 4 * x = \frac{2}{10} * 8 * 6 * 3$$

$$\frac{10}{2}x = \frac{(8 * 6 * 3)}{(6 * 4)}$$

$$5x = 6$$
$$x = \frac{6}{5} = 1.2$$

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A worker places a rectangular electrical box so that it is entirely co &nbs [#permalink] 05 Dec 2017, 09:39
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