Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 07
10:00 AM PDT
-11:00 AM PDT
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost. - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway - Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
02 Jun 2020, 04:30
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:26) correct
20%
(02:18)
wrong
based on 61
sessions
History
Date
Time
Result
Not Attempted Yet
AB and CD are two parallel chords in a circle with centre O and radius 5cm. If the length of AB = 6cm, CD = 8cm. Find the perpendicular distance between the two chords.
A. 4 cm
B. 5 cm
C. 6 cm
D. 7 cm
E. 8 cm
Attachment:
1.png [ 13.53 KiB | Viewed 5638 times ]
02 Jun 2020, 04:51
Kudos
Bookmarks
is it 7??
there are 2 isoceles triangles with 2 equal sides of 5.
The 1st triangle has a base of 8 (Chord AB) and the 2nd of 6 (Chord CD).
you take a perpendicular line from the Radius to both CD and AB (one base (Chord) is divided to 3 and 3, the other to 4 and 4 (SINCE THEY ARE PARALLEL) and you get the ratio of right angle triangle as: 3:4:5 and 4:3:5.
so the 1st perpendicular is 3 and the other is 4. so i go with 7 D.
there are 2 isoceles triangles with 2 equal sides of 5.
The 1st triangle has a base of 8 (Chord AB) and the 2nd of 6 (Chord CD).
you take a perpendicular line from the Radius to both CD and AB (one base (Chord) is divided to 3 and 3, the other to 4 and 4 (SINCE THEY ARE PARALLEL) and you get the ratio of right angle triangle as: 3:4:5 and 4:3:5.
so the 1st perpendicular is 3 and the other is 4. so i go with 7 D.
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 10 Aug 2026
Posts: 3,095
Own Kudos:
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
02 Jun 2020, 06:40
Kudos
Bookmarks
Connect OC OD OA and OB
Area of triangle OAB is
=> √S(S-A)(S-B)(S-C)
(Half perimeter) S = AO+OB+AB/2 => 5+5+6/2
=> S = 8
=> √8(8-5)(8-5)(8-6)
=> √8(3)(3)(2)
=> √2*2*2(3)(3)(2)
=> 2*2*3 = 12 = Area of ABO
Let the perpendicular on AB from centre be OM
Also area of ABO = 1/2*AB*OM
=> 12 = 1/2*6*OM
=> 4 = OM
Area of triangle OCD is
=> √S(S-A)(S-B)(S-C)
(Half perimeter) S = CO+OD+CD/2 => 5+5+8/2
=> S = 9
=> √9(9-5)(9-5)(9-8)
=> √9(4)(4)(1)
=> √3*3(2*2)(2*2)(1)
=> 2*2*3 = 12 = Area of CDO
Let the perpendicular on CD from centre be ON
Also area of CDO = 1/2*CD*ON
=> 12 = 1/2*8*ON
=> 3 = ON
The perpendicular distance between two chords = ON+OM = 4+3 = 7
Answer is D
Posted from my mobile device
Area of triangle OAB is
=> √S(S-A)(S-B)(S-C)
(Half perimeter) S = AO+OB+AB/2 => 5+5+6/2
=> S = 8
=> √8(8-5)(8-5)(8-6)
=> √8(3)(3)(2)
=> √2*2*2(3)(3)(2)
=> 2*2*3 = 12 = Area of ABO
Let the perpendicular on AB from centre be OM
Also area of ABO = 1/2*AB*OM
=> 12 = 1/2*6*OM
=> 4 = OM
Area of triangle OCD is
=> √S(S-A)(S-B)(S-C)
(Half perimeter) S = CO+OD+CD/2 => 5+5+8/2
=> S = 9
=> √9(9-5)(9-5)(9-8)
=> √9(4)(4)(1)
=> √3*3(2*2)(2*2)(1)
=> 2*2*3 = 12 = Area of CDO
Let the perpendicular on CD from centre be ON
Also area of CDO = 1/2*CD*ON
=> 12 = 1/2*8*ON
=> 3 = ON
The perpendicular distance between two chords = ON+OM = 4+3 = 7
Answer is D
Posted from my mobile device
