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24 Mar 2008, 09:13
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N
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ABCD is a quadrilateral. Is the sum of angles ABC and CDA is equal to the sum of angles BCD and DAB?
(1) Circle O is inscribed in ABCD.
(2) Circle O is circumscribed about ABCD.
Please explain your answer. I thought this question was straight forward, but apparently I got tricked.
cheers
(1) Circle O is inscribed in ABCD.
(2) Circle O is circumscribed about ABCD.
Please explain your answer. I thought this question was straight forward, but apparently I got tricked.
cheers
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Hi there,
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24 Mar 2008, 10:12
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B
For a square the sum of angles ABC and CDA is equal to the sum of angles BCD and DAB under both conditions.
1. we can construct a rhombus (see a drawing) in which the sums will not be equal. insufficient
2. for any quadrilateral inscribed in a circle, the sums will always be equal (see the drawing). sufficient
For a square the sum of angles ABC and CDA is equal to the sum of angles BCD and DAB under both conditions.
1. we can construct a rhombus (see a drawing) in which the sums will not be equal. insufficient
2. for any quadrilateral inscribed in a circle, the sums will always be equal (see the drawing). sufficient
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24 Mar 2008, 10:35
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dude, you're just insane! hehe...the OA is B. Is there any quant problem that you just can't answer?? there has to be one...lol...thanks anyway...
