According to a car dealer's sales report, 1/3 of the cars sold during

Question

According to a car dealer's sales report, 1/3 of the cars sold during a certain period were sedans and 1/5 of the other cars sold were station wagons. If N station wagons were sold during that period, how many sedans, in terms of N, were sold?

A. 2N/15

B. 3N/5

C. 5N/3

D. 5N/2

E. 15N/2

A. 2N/15

B. 3N/5

C. 5N/3

D. 5N/2

E. 15N/2

taniad · Accepted Answer

Ans: D= 5N/2
Let cars sold=x
Sedans sold= 1/3(x)
Other Cars= 2/3(x)
Station wagons sold= 1/5(2/3(x))=2x/15=>N
=> x= 15N/2
Sedans=1/3(15N/2)= 5N/2

Akash720 · Answer

Sedans sold = X/3
Station wagons sold = 1/5 of left (other cars) =  1/5*2X/3 = 2X/15 
2X/15 = N (Given)
X = 15N/2
X/3 = 5N/2

+1 for D

abhishekdadarwal2009 · Answer

Let total number of cars be 15,(smart number assumed based of 1/3,1/5).
then the sedans will be 5 and station wagon will be 3. ,
if N is the number of station wagon then sedans=?

we can just put the value of N in the options to get correct value.

so we put n=3 and get C as the correct answer.

Option C.

EgmatQuantExpert · Answer

Solution 
  Given:  
 • During a certain period,  \frac{1}{3}  of the cars sold were sedans
•  \frac{1}{5}  of the other cars sold were station wagons
• N station wagons were sold during that period

To find:  
 • The number of sedans sold in terms of N

Approach and Working:   
 • Let the total number of cars sold be X.
 o Implies,  \frac{X}{3}  cars sold were sedans, and
o Remaining  \frac{2X}{3}  were other cars 
• So, number of station wagons sold =  \frac{1}{5} of \frac{2X}{3} = N 
 o Implies,  \frac{2X}{15} = N 
o  X = \frac{15N}{2}  
• Thus,  \frac{X}{3} = \frac{5N}{2}

Therefore, the number of sedans sold during that period =  \frac{5N}{2}

Hence, the correct answer is option D.

Answer: D

https://e-gmat.com/blogs/wp-content/uploads/2018/08/Ability-Quiz-WP-e1533292133520.png

NYDukie · Answer

Any similar questions to practice for this topic?  Bunuel

Eternal · Answer

(Solving by plugging nos.)

Since LCM of 3 and is 5 is 15. 
Take total no of cars sold as 15

1/3 sold were sedans.  so 5 sedans were sold. 
remaining 15-5= 10

1/5 of remaining sold were station wagons, so  2 station wagons sold  depicted by N.

Plug the value in options and (D) is the answer.

Bunuel · Answer

Check this: https://gmatclub.com/forum/a-total-of-x ... fl=similar

Archit3110 · Answer

let total cars sold = 15
so sedan ; 15/3 ; 5
left with 10 cars ; out of which 10/5 ; 2 are wagons
so N=2 option D 5N/2 is correct for sedans

pratiksha1998 · Answer

Let the total number of cars be x
Acc to the question number of sedans sold = x/3
Cars left = x-x/3
Given that 1/5*(x-x/3) =N
Solving for x/3; we get 5N/2
Ans = 5N/2

GMATCoachBen · Answer

Here's a very similar problem that you may want to try:  https://gmatclub.com/forum/at-a-certain-pizzeria-1-8-of-the-pizzas-sold-in-one-week-were-mushroo-168060.html#p1337525

And my solution video for that one:  https://youtu.be/13onWibgsqg

Video solution for this one:

https://www.youtube.com/watch?v=pdnr6XZPvZ0

A key habit is to read carefully!  A common mistake is to misread the "OF ____" part ; here, we must not overlook the word "1/5 of the OTHER cars."

0:10 Method 1  — Pick a number for the total cars, "T". We use the Least Common Multiple (LCM) of 3 and 5, which is 15.

1:36 Method 2 : Fast Algebra. It's essential to get very fluent translating words to equations.

bumpbot · Answer

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According to a car dealer's sales report, 1/3 of the cars sold during

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