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11 Apr 2019, 23:50
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:31) correct
25%
(02:43)
wrong
based on 102
sessions
History
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Result
Not Attempted Yet
According to Nielsen Media Research, approximately 68% of all U.S. households with television have cable TV. Seventy-five percent of all U.S. households with television have two or more TV sets. Suppose 56% of all U.S. households with television have cable TV and two or more TV sets. A U.S. household with television is Randomly selected. What is the probability that the household has neither cable TV nor two or more TV sets?
A. 0.13
B. 0.15
C. 0.17
D. 0.19
E. 0.25
A. 0.13
B. 0.15
C. 0.17
D. 0.19
E. 0.25
saukrit
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11 Apr 2019, 23:59
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4 types of users are there
1. With Television but without Cable TV or 2+ TV Sets = 100- (12+19+56) =13
2. With Television with Cable but without 2+ TV Sets =68-56 =12
3. With Television with 2+ TV sets but without Cable TV = 75-56=19
4. With all 3 (Television, cable TV an 2+ TV sets) = 56
Probability that the household has neither cable TV nor two or more TV sets = 13/100= 0.13
Hence , Answer is A
1. With Television but without Cable TV or 2+ TV Sets = 100- (12+19+56) =13
2. With Television with Cable but without 2+ TV Sets =68-56 =12
3. With Television with 2+ TV sets but without Cable TV = 75-56=19
4. With all 3 (Television, cable TV an 2+ TV sets) = 56
Probability that the household has neither cable TV nor two or more TV sets = 13/100= 0.13
Hence , Answer is A
Archit3110
12 Apr 2019, 11:25
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gmatbusters
use 2x2 matrix
let total sample size = 100
---------cable tv-------no cable tv------total
>2 tv----56------------19------------75
<2tv-----12-----------13-------------25
total------68----------32-------------100
so no cable and <2 tv sets = 13
P (household has neither cable TV nor two or more TV sets) =13/100 ; 0.13
IMO A
