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# According to the incomplete table above, if each of the 6 te

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Intern
Joined: 27 Nov 2004
Posts: 25
Location: Vienna, Austria
According to the incomplete table above, if each of the 6 te  [#permalink]

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19 Jan 2005, 14:28
1
19
00:00

Difficulty:

15% (low)

Question Stats:

82% (01:48) correct 18% (02:06) wrong based on 362 sessions

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Team / No of games won

A 4
B 7
C 9
D 2
E 2
X ?

According to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game.)

(A) 4
(B) 5
(C) 6
(D) 8
(E) 10
Intern
Joined: 11 Jan 2005
Posts: 14

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19 Jan 2005, 14:35
1
6

6C2= 15 single games, & 30 in total.

won by others= 24

30-24= 6
VP
Joined: 18 Nov 2004
Posts: 1154

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19 Jan 2005, 14:55
"C".

Total games = 6C2 = 15 groups....but each play twice...so 30 games....24 won by others.....so 6 won by x.
Manager
Joined: 08 Jul 2009
Posts: 135

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10 Jul 2009, 10:05
1
Team Number of Games Won
A 4
B 7
C 9
D 2
E 2
X

According to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game.)
(A) 4
(B) 5
(C) 6
(D) 8
(E) 10
Manager
Joined: 04 Jun 2008
Posts: 178

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10 Jul 2009, 10:09
2
ans should be 6

each of 6 teams play 2 games with each of the other teams
so total of 30 games played........[ 2*(5+4+3+2+1)] = 30

there should be 30 wins, bcoz there were no ties.

total number of wins given in table adds up to 24, so X won remaining 6 games.
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Re: According to the incomplete table above, if each of the 6 te  [#permalink]

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07 May 2015, 21:38
2
Hi All,

If you're comfortable using the Combination Formula, then calculating that 30 games were played is a fairly straight-forward task. If you're not comfortable with that formula yet, here's another way to figure out that 30 games were played.....

The teams are A, B, C, D, E and X

Team A plays each of the other 5 teams TWICE, so that's 2(5) = 10 games

Since B ALREADY played Team A twice, we won't count those games again; Team B plays each of the remaining 4 teams twice, so that's 2(4) = 8 games

Since C ALREADY PLAYED Team A and Team B, we won't count those games again, Team C plays each of the remaining 3 teams twice, so that's 2(3) = 6 games.

This pattern continues, giving us...

10+8+6+4+2+0 = 30 total games.

From there, the rest of the work is based on addition.

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Re: According to the incomplete table above, if each of the 6 te  [#permalink]

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05 Jun 2016, 09:03
2
Dr_Friedrich wrote:
Team / No of games won

A 4
B 7
C 9
D 2
E 2
X ?

According to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game.)

(A) 4
(B) 5
(C) 6
(D) 8
(E) 10

Team A played 5*2= 10 matches with other teams
Team B played 4*2= 8 matches with other teams
Team C played 3*2= 6 matches with other teams
Team D played 2*2= 4 matches with other teams
Team E played 2 matches

Total Matches played= 30

Total Matches won by teams other than team X= 24

Total matches won by team X = 30-24= 6

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Joined: 31 May 2015
Posts: 129
Re: According to the incomplete table above, if each of the 6 te  [#permalink]

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28 Jun 2016, 11:48
6P2 = 30 games

24 won - 30 games = 6 won ans. C.
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According to the incomplete table above, if each of the 6 te  [#permalink]

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28 Jun 2016, 16:26
(n)(n-1)=6*5=30 total games=30 total wins
30-24=6
team x won 6 games
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Re: According to the incomplete table above, if each of the 6 te  [#permalink]

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30 Dec 2018, 10:02
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Re: According to the incomplete table above, if each of the 6 te   [#permalink] 30 Dec 2018, 10:02
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