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ariyanak
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@ariyanak­After taking six practice exams, Albert is reviewing the number of mistakes he made. On the first five exams, he made 7, 4, 8, 6 and 10 mistakes respectively.

In the table below, select a number of mistakes he could make on the 6th exam such that the mean number of mistakes is equal to the median number of mistakes. Then select a number of mistakes he could make on the 6th exam such that the mean (average) is greater than the median. Make only two selections, one in each column.­
Let the mistake made on the 6th exam be x.
Mistakes = {4,6,7,8,10,x} : x is unknown: Median number of mistakes = {7,(x+7)/2}: x is NOT greater than 7 since x is a positive integer.

Mean number of mistakes = (7+4+8+6+10+x)/6 = (35+x)/6

The number of mistakes he could make on the 6th exam such that the mean number of mistakes is equal to the median number of mistakes.
x = 7; Mean number of mistakes = 7 = Median number of mistakes

The number of mistakes he could make on the 6th exam such that the mean (average) is greater than the median.
(35+x)/6 > 6.5
x > 4; x = 5


Mean=MedianMean > Median
75
­
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