Answer to this question cannot be E, it's B.

After winning 80 percent of the fi…rst 40 games it played, Team A lost all the remaining games it played. How many total games did Team A play?

Team A lost 0.2*40=8 of the first 40 games and all the remaining games, say x. So, total games lost is 8+x and total games played is 40+x.

(1) Team A lost all of its games against Team B, which won 75 percent of its total games. Clearly not sufficient.

(2) Team A lost exactly 1/3 of all the games it played --> 8+x=1/3*(40+x), only one unknown, hence we can solve for it. Sufficient.

Answer: B.

Hope it's clear.
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Even though I answered it wrong, I think I know why.

Team won 80% of first 40 games => Win = 32 Lost/ Tie 8 out of first 40. and lost all after wards. So total Win (32) + Lost (x) + Tie/ Lost (8)
1) Team B won 75% of games it played and Team A lost all against it. Do not know how many teams are there over all. How many games each team plays agains another.
2) Team lost 1/3 of the game. **HERE I MADE MISTAKE** lost =1/3 NOT EQUALs TO 2/3 won because there could be tie in some of the 8 games out of first 40. So, not sufficient.

Hence E.

I don't think the question assumes that ties are possible.

Hi,

I used a tabular format as mentioned below
- - 40 Games - - X-40 Games
Won - - 32 -------0
Lost- - 8 ---------X-40

Statement 1 : We have no clue if Team A played B C D E hence insufficient
Statement 2 : X/3 = 8 + X - 40
Sufficient
Thus B

Hope this helps

Statement 2 is sufficient because we know how many it won and how many it lost.

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