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18 Dec 2019, 03:33
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Difficulty:
25%
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Question Stats:
83% (02:36) correct
17%
(02:44)
wrong
based on 113
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Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?
A. 80
B. 85
C. 90
D. 95
E. 100
Are You Up For the Challenge: 700 Level Questions
A. 80
B. 85
C. 90
D. 95
E. 100
Are You Up For the Challenge: 700 Level Questions
firas92
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Joined: 16 Jan 2019
Last visit: 02 Dec 2024
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Location: India
Concentration: General Management
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GMAT 1: 740 Q50 V40
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18 Dec 2019, 05:44
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Lets say Beatrice met Albert at \(d\) miles from Megiddo
Beatrice traveling at \(x\) mph covers these \(d\) miles in \(2\) hours while Albert traveling at \(60mph\) covers the same \(d\) miles in \(2\) hours and \(50\) minutes or \(2\frac{5}{6}=\frac{17}{6} hours\)
\(60*\frac{17}{6}=d\)
\(x*2=d\)
Therefore, \(60*\frac{17}{6}=2x\)
\(x=85mph\)
Answer is (B)
Beatrice traveling at \(x\) mph covers these \(d\) miles in \(2\) hours while Albert traveling at \(60mph\) covers the same \(d\) miles in \(2\) hours and \(50\) minutes or \(2\frac{5}{6}=\frac{17}{6} hours\)
\(60*\frac{17}{6}=d\)
\(x*2=d\)
Therefore, \(60*\frac{17}{6}=2x\)
\(x=85mph\)
Answer is (B)
19 Dec 2019, 05:56
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Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?
A. 80
B. 85
C. 90
D. 95
E. 100
A. 80
B. 85
C. 90
D. 95
E. 100
B to X took 15:20 - 13:20 = 2 hrs
A to X took 16:10 - 13:20 = 2 hours + 50 mins = 2+5/6 = 17/6 hrs
distance = rate * time
b's rate * 2hrs = d
a's rate * 17/6hrs = d
b's rate * 2hrs = a's rate * 17/6hrs, 2b = 60*17/6, b=85
Ans (B)
