Solution
Given:• All the students of a class are to be divided into 20 individual study groups.
To find:• The minimum number of candidates present in the least populated group.
Analysing Statement 1As per the information given in statement 1, the total number of students in the class in 238.
• From this statement, we do not have any information about the number of students in the least populated of the 20 groups.
Hence, statement 1 is not sufficient to answer the question.
Analysing Statement 2As per the information given in statement 2, any group cannot have more than 20% if the number of students of any other group.
• Let us assume the minimum number of students present in the least populated group is n
• Therefore, the maximum number of students present in any of the groups will be 1.2n
Now to minimize n, we should have only one group with n students, and all other groups should have maximum possible number of students (which is 1.2n).
Therefore, we can say
• Total number of students = n + 19 x 1.2n = n + 22.8n = 23.8n
But from this statement, we cannot determine the value of n, as we don’t know the total number of students.
Hence, statement 2 is not sufficient to answer the question.
Combining Both StatementsCombining both statements, we can say
• 23.8n = 238
Or, \(n = \frac{238}{23.8} = 10\)
Therefore, the minimum number of students present in the least populated group is 10.
Hence, the correct answer is option C.
Answer: CBut the same can be found by the 1st statement itself - 238 students and 20 groups - if 1 group is of 10 , rest 228 can be evenly divided in 19 groups , 12 per group, so the least populated group is 10. So in that case answer would be A.Let me know if this is not correct.