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Now I see the 2H, thank you both. Originally I wasn't understanding why it was just over H, but now it makes sense.
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Last one for now: I will post without the answer so everyone can practice. (Will post answer later.) I apologize if I don't know the proper area of the forum for this, but I need help understanding how to set this up. So if you could all explain your logic, that would be great.


An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in mph, for these 2 activities combined?

A) (R-Q)/H
B) (R-Q)/2H
C) [2(R+Q)]/H
D) [2(R+Q)]/2H
E) (R+Q)/2H




I don't understand the logic behind the choices containing 2H.


:) another E

AVERAGE SPEED = TOTAL DISTANCE /TOTAL TIME

TOTAL DISTANCE R+Q
TOTAL TIME H +H = 2H



:wink:
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Hi All,

As far as story problems go, this one is fairly easy from a "logic" standpoint. You can also solve it by TESTing VALUES.

R = 4
H = 2
Q = 6

So the athlete runs 4 miles in 2 hours, then bikes 6 miles in another 2 hours.

Total Distance = 4+6 = 10 miles
Total Time = 2+2 = 4 hours
Average speed = 10/4 = 2.5 miles/hr.

Plugging these values into the answer choices gives us just one match...

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Rate x Time = Distance
R/H x H = R
Q/H x H = Q

Avg speed = total distance/ total time
= (R+Q)/ 2H
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w07
An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in miles per hour, for these two activities combined?

(A) (R-Q)/H
(B) (R-Q)/2H
(C) [2(R+Q)]/H
(D) [2(R+Q)]/2H
(E) (R+Q)/2H


We need to determine average speed:

average speed = total distance/total time

average = (R + Q)/(H + H) = (R + Q)/2H

Answer: E
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Answer E

For cycle = X * H = R
For Bike = X * H = Q

Average = total distance / total time
= R + Q / 2H
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w07
An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in miles per hour, for these two activities combined?

(A) (R-Q)/H
(B) (R-Q)/2H
(C) [2(R+Q)]/H
(D) [2(R+Q)]/2H
(E) (R+Q)/2H

Distance = R+Q
Time= H+H= 2H
Distance = Time * Speed
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At first, I interpreted R as a rate (i.e., R mph) and Q as another rate (Q mph), because I saw "miles per hour" in the question and assumed both values were rates. Using this logic, I calculated the average rate as (HR+HQ)/2H = H(R+Q)/2H = R+Q/H which was not part of the given answers. I ended up picking the right answer. However, how do you usually catch this distinction quickly during the test to avoid this kind of mistake?
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YolandaSami
An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in miles per hour, for these two activities combined?

(A) (R-Q)/H
(B) (R-Q)/2H
(C) [2(R+Q)]/H
(D) [2(R+Q)]/2H
(E) (R+Q)/2H

At first, I interpreted R as a rate (i.e., R mph) and Q as another rate (Q mph), because I saw "miles per hour" in the question and assumed both values were rates. Using this logic, I calculated the average rate as (HR+HQ)/2H = H(R+Q)/2H = R+Q/H which was not part of the given answers. I ended up picking the right answer. However, how do you usually catch this distinction quickly during the test to avoid this kind of mistake?

The question says the athlete runs R miles in H hours, so R is the distance, not the rate. If you wanted the per hour rate, it would be distance/time = R/H miles per hour. Same for biking: Q is the distance, and the biking rate would be Q/H miles per hour.

So whenever you see something like “runs R miles in H hours,” treat R as distance. Watch the units closely. If it doesn't say “R miles per hour,” then R is not a per hour rate.
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