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Joined: 07 Jul 2005
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An athlete runs R miles in H hours, then rides a bike Q miles in the
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Updated on: 11 Jan 2015, 23:51
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An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in miles per hour, for these two activities combined? (A) (RQ)/H (B) (RQ)/2H (C) [2(R+Q)]/H (D) [2(R+Q)]/2H (E) (R+Q)/2H
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Originally posted by w07 on 16 Jul 2005, 06:53.
Last edited by Bunuel on 11 Jan 2015, 23:51, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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16 Jul 2005, 09:00
Ans is E  R + Q / 2H
formular for avg speed is total distance / total time
Time spent running = H and the time spent biking = H
total time is H + H = 2H
Total distance is R + Q
Thus E



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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16 Jul 2005, 09:36
Welcome to GMAT Club, w07
Combined distance traveled = R + Q
Combined time = H + H ( the athelete runs for H hours and bikes for another H hours)
Thus, the combined time = 2H
Therefore, Average speed of two activities combined
= combined distance / combined time
= (R + Q) / (2H)
do you see how you get 2H?
Praetorian



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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16 Jul 2005, 14:51
Now I see the 2H, thank you both. Originally I wasn't understanding why it was just over H, but now it makes sense.



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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17 Jul 2005, 06:57
w07 wrote: Last one for now: I will post without the answer so everyone can practice. (Will post answer later.) I apologize if I don't know the proper area of the forum for this, but I need help understanding how to set this up. So if you could all explain your logic, that would be great.
An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in mph, for these 2 activities combined?
A) (RQ)/H B) (RQ)/2H C) [2(R+Q)]/H D) [2(R+Q)]/2H E) (R+Q)/2H
I don't understand the logic behind the choices containing 2H.
another E
AVERAGE SPEED = TOTAL DISTANCE /TOTAL TIME
TOTAL DISTANCE R+Q
TOTAL TIME H +H = 2H



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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11 Jan 2015, 23:50
Hi All, As far as story problems go, this one is fairly easy from a "logic" standpoint. You can also solve it by TESTing VALUES. R = 4 H = 2 Q = 6 So the athlete runs 4 miles in 2 hours, then bikes 6 miles in another 2 hours. Total Distance = 4+6 = 10 miles Total Time = 2+2 = 4 hours Average speed = 10/4 = 2.5 miles/hr. Plugging these values into the answer choices gives us just one match... Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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09 Feb 2015, 09:30
Rate x Time = Distance R/H x H = R Q/H x H = Q
Avg speed = total distance/ total time = (R+Q)/ 2H



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Re: An athlete runs R miles in H hours, then rides a bike Q miles in the
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29 Jan 2018, 10:12
w07 wrote: An athlete runs R miles in H hours, then rides a bike Q miles in the same number of hours. Which of the following represents the average speed, in miles per hour, for these two activities combined?
(A) (RQ)/H (B) (RQ)/2H (C) [2(R+Q)]/H (D) [2(R+Q)]/2H (E) (R+Q)/2H We need to determine average speed: average speed = total distance/total time average = (R + Q)/(H + H) = (R + Q)/2H Answer: E
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