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# Ann and Pierre purchased \$37 worth of French fries.

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Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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15 Jul 2014, 23:45
3
00:00

Difficulty:

55% (hard)

Question Stats:

65% (01:48) correct 35% (01:58) wrong based on 180 sessions

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Ann and Pierre purchased \$37 worth of French fries. Ann spent \$3 on each order of French fries she bought, and Pierre spent \$5 on each order of French fries he bought. How many orders of French fries did Ann purchase?

(1) Ann and Pierre would have spent a total of \$111 if Ann had spent \$9 on each order of French fries she purchased, and Pierre had spent \$15 on each order of French fries he purchased.

(2) Ann and Pierre purchased a total of 9 orders of French fries.

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Re: Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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16 Jul 2014, 00:22
1
1
If we let "a" be the number of orders by Anna and "p" be the number of order by Pierre, the information supplied:
* 37 = 3a + 5p
* a and p are integers

(1) tells us that 111 = 9a + 15p
This simplifies to 37 = 3a + 5p
No new information given.
Not enough information to solve the equation (could be either a = 9 and p = 2; or a = 4 and p = 5

(2) tells us that a + p = 9
substituting a = 9 - p into 37 = 3a + 5p yields a = 4.
Sufficient.

Therefore, B.

I would definitely not classify this question as 600-700... more like sub-600...
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Re: Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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16 Jul 2014, 01:56
dbaremberg wrote:
Ann and Pierre purchased \$37 worth of French fries. Ann spent \$3 on each order of French fries she bought, and Pierre spent \$5 on each order of French fries he bought. How many orders of French fries did Ann purchase?

(1) Ann and Pierre would have spent a total of \$111 if Ann had spent \$9 on each order of French fries she purchased, and Pierre had spent \$15 on each order of French fries he purchased.

(2) Ann and Pierre purchased a total of 9 orders of French fries.

If we let "a" be the number of orders by Anna and "p" be the number of order by Pierre, the information supplied:
* 37 = 3a + 5p
* a and p are integers

(1) tells us that 111 = 9a + 15p
This simplifies to 37 = 3a + 5p
No new information given.
Not enough information to solve the equation (could be either a = 9 and p = 2; or a = 4 and p = 5

(2) tells us that a + p = 9
substituting a = 9 - p into 37 = 3a + 5p yields a = 4.
Sufficient.

Therefore, B.

I would definitely not classify this question as 600-700... more like sub-600...

Agree, the question is as simple as it gets.
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Re: Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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05 Aug 2014, 01:18
Let orders of Ann be x and orders of Pierre be y, then

3x + 5y = 37

We are looking for x.

(1) 9x + 15 y = 111. It's a trap! If you combine the equations you will get nothing, since 3 x first equation = second equation. IS.
(2) x + y = 9 --> y = 9-x --> set in equation from question, SUFF.

B.
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Re: Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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06 Aug 2014, 10:55
Gnpth wrote:
Ann and Pierre purchased \$37 worth of French fries. Ann spent \$3 on each order of French fries she bought, and Pierre spent \$5 on each order of French fries he bought. How many orders of French fries did Ann purchase?

(1) Ann and Pierre would have spent a total of \$111 if Ann had spent \$9 on each order of French fries she purchased, and Pierre had spent \$15 on each order of French fries he purchased.

(2) Ann and Pierre purchased a total of 9 orders of French fries.

B

For the question that involves 2 equations and 2 variables, always check to see if you solve it from the equations.
3A + 5P = 37, if you multiply this by 3, you get (1) 9A + 15P = 111
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Re: Ann and Pierre purchased \$37 worth of French fries.  [#permalink]

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30 Aug 2018, 10:38

Let a be the number of orders that Ann purchased and let p be the number of orders that Pierre purchased. From the question stem, we can set up the equation 37 = 3a + 5p, which expresses the total cost of the French fries purchased by Ann and Pierre. In order to solve for the number of orders of French fries that Ann bought, we need to be able to set up another distinct equation that contains the variables a and p.

Statement (1): insufficient. From this information, we can write the equation 111 = 9a + 15b. We have another equation relating a and p, but is it distinct? No. Upon closer inspection, this is simply the result of multiplying both sides of the original equation 37 = 3a + 5p by 3. We can eliminate choices (A) and (D).

Statement (2): sufficient. From this statement, we can set up the equation 9 = a + b. Is this equation distinct from the original equation? Yes. This is therefore sufficient to find the value of a, or the number of orders of French fries that Ann purchased. Choice (B) is correct.
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Re: Ann and Pierre purchased \$37 worth of French fries.   [#permalink] 30 Aug 2018, 10:38
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