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lastochka
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lastochka
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weird question. E it is
1) 3^4n + 1 = 81^n + 1 --> introduction of "m" is intriguing. "m" could be any number which makes it that 81^n + 1 equals something with 0 as remainder
2) there could be some fraction "n" which makes it that when 81^n + 1 is divided by 10, the remainder could be 0. Haven't work it out yet.

I suspect the quality of this question though
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ashkg
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I go for D

1. let E= 3^4n + 1 = 81^(2m+1) + 1

81 to the power of anything will end in 1

so E will always end in 2. Not divisible by 10 . Remainder can't be 0. Therefore , Sufficient

2. let E= 3^4n+1 . Here n>4

E = 81^n + 1

81 to the power of anything will end in 1

so E will always end in 2. Not divisible by 10 . Remainder can't be 0. Therefore , Sufficient

Answer should be D.

- ash
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Hi

3^6 will give 9 as the last number...then 9+1=10, which is divisible by 10. (Note, it is not given that n is an integer- tricky one :-D ).

The same explaination goes for statement A and B.

Hence the answer should be E.
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I can't understand how you came up with 3^6 ?

B says n>4

and we want to find out what 3^4n ends in......which should be 1 as n>4.

I still feel B is sufficient.


For A, it depend on the value of m.

If m is +ve integer or 0, exp is definitely not div by 10.
If 2m+1 = 1/2, exp is div by 10.
For all other values of m, exp would not be div by 10.

Therefor A is insufficient. ( assuming we dont have any more info on m)

- ash.

OA and more info on n and m would clear things :)
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Hi

Let us consider statment by statement.

The stem says...if (3^4n)+1 is divided by 10, can the remainder be 0?

Statement 1. n=2m+1 (If n=30) then the equation will result in divisble by 10. Fro N to be 30, m=14.5. (It has not been mentioned that either N or M is a integer. Hence M can take any value. FOr other values, the result may be not divisible by 10. Hence NOT SUFFICIENT.

2. n>4 - The same case as above. It is not been mentioned that N is an integer, hence n can take a value 30 for the equation to be divisible by 10. Or any other value that wud result in as not divisible by 10. Hence NOT SUFFICIENT.

Combining both the cases. - We do not know the value of M. Hence it is not possible to get one value of N to say that the equation is divisible by 10. NOT SUFFICIENT.

Hence the answer is E.

Correct me if I am wrong. Am i missing something here.

Regards
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Hi

I missed giving another value of N where the equation wud result in as a divisible of 10.

When N=14, then the result wud come to remainder 0, when divided by 10.

Regards
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true......my assumption of n ( and earlier m ) being an Integer is wrong :)

therefore B and A are both insufficient......

- ash
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lastochka
another one whose solution eludes me

if (3^4n)+1 is divided by 10, can hte remainder be 0?
1. n=2m+1
2. n>4

pls explain your answer


3^4n + 1 : n = 0 => remainder = 2,
n = 1 => remainder = 2,
n = 2 => remainder = 2,
n = 3 => remainder = 2,
n = 4 => remainder = 2,

3^4n = 81^n = (8*10+1)^n = 10*m + 1.

=> 3^4n + 1 is NEVER divided by 10, therefore, we can't answer this question.
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Emmanuel
lastochka
another one whose solution eludes me

if (3^4n)+1 is divided by 10, can hte remainder be 0?
1. n=2m+1
2. n>4

pls explain your answer

3^4n + 1 : n = 0 => remainder = 2,
n = 1 => remainder = 2,
n = 2 => remainder = 2,
n = 3 => remainder = 2,
n = 4 => remainder = 2,

3^4n = 81^n = (8*10+1)^n = 10*m + 1.

=> 3^4n + 1 is NEVER divided by 10, therefore, we can't answer this question.


I fell in the same trap as you when I originally looked at this question, and I couldn't believe that the answer provided, D, was correct.
If n=1.5, then (3^4n)+1 gets us 730, which is fully divisible by 10.
just read ashkg's post above for further clarification.

Ashkg, great job solving this one!



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