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30 Apr 2020, 11:06
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
66% (01:50) correct
34%
(01:51)
wrong
based on 38
sessions
History
Date
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Not Attempted Yet
Anya bought a cake, which is in the shape of a regular hexagon. She cuts the cake, into two halves, along one of the diagonals which pass through the center of the hexagon. If the length of one side of the cake is “a” cm, what is the perimeter of one of the pieces of the cake?
A. 4a
B. (3 + √3)a
C. 5a
D. (4 + √3)a
E. (4 + 2√3)a
A. 4a
B. (3 + √3)a
C. 5a
D. (4 + √3)a
E. (4 + 2√3)a
30 Apr 2020, 20:31
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Strange that her cake is 2- dimensional. Anyways,
BAX and CDY are (30-60 and 90) triangle.
Hence, \(AX= YD = \frac{a}{2}.\)
We get \( AD = \frac{a}{2}+a+\frac{a}{2} = 2a\)
the perimeter of one of the pieces of the cake = \(AB+BC+CD+AD= a+a+a+2a = 5a\)
BAX and CDY are (30-60 and 90) triangle.
Hence, \(AX= YD = \frac{a}{2}.\)
We get \( AD = \frac{a}{2}+a+\frac{a}{2} = 2a\)
the perimeter of one of the pieces of the cake = \(AB+BC+CD+AD= a+a+a+2a = 5a\)
Kritisood
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30 Apr 2020, 20:35
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Hi Kritisood,
I have solved the problem and uploaded a image for better understanding.
PS: Kudos if you found the solution helpful.
I have solved the problem and uploaded a image for better understanding.
PS: Kudos if you found the solution helpful.
Attachments
solution.jpeg [ 104.01 KiB | Viewed 2075 times ]
