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chanmat
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GMATT73
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skandhadarshan
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chanmat
Are atleast 20 percent of the people in city H who are at least 30 years old bilingual?

1. In city H, 30 percent of the population is at least 30 years old.
2. In city H, of the population 30 years old or older, 18 percent of the women and 17 percent of the men are bilingual



Lets start from 2.
If 2 was enuf
lets say there are 1000 men and 100 women then the total bilingual=170+18=198 =19.8% < 20%
lets say vice versa 1000 men and 1000 women then total=180+170=350=35% > 20%

Hence nothing cann be told from B alone.

From 1 alone nothing can be told reg bilingual

Consider both,nothing can be predicted.

Hence answer is E
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Viperace
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Agree with E

When u pull everything together, this piece of info is missing:
Fraction of Female/Male
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jainvik7
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Correct me if I am wrong. I am trying to club the reasoning provided by
skandhadarshan and GMATT73.

Let us say ( men + women ) = 2000

From st1 - 30 percent of this population is atleast 30 years old.
30 % of 2000 = 600.

From st2 - Though we dont know the exact fraction of males and females I would take the extreme case 99 % male and 1 % female.

So the number of males at least 30 yrs --> 99 % of 600 = 594 (approx)
Females at least 30 yrs --> 1 % of 600 = 6

18 % of 594 are bilingual (MALES) = 107 (approx)
17 % of 6 are bilingual (FEMALES) = 2 (approx)
========================================
Total bilingual = 109 < 20 % of 600.

Is this reasoning incorrect ? Please do point out where I went wrong.
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GMATT73
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jainvik7
Correct me if I am wrong. I am trying to club the reasoning provided by
skandhadarshan and GMATT73.

Let us say ( men + women ) = 2000

From st1 - 30 percent of this population is atleast 30 years old.
30 % of 2000 = 600.

From st2 - Though we dont know the exact fraction of males and females I would take the extreme case 99 % male and 1 % female.

So the number of males --> 99 % of 600 = 594 (approx)
Females --> 1 % of 600 = 6

18 % of 594 are bilingual (MALES) = 107 (approx)
17 % of 6 are bilingual (FEMALES) = 2 (approx)
========================================
Total bilingual = 109 < 20 % of 600.

Is this reasoning incorrect ? Please do point out where I went wrong.


Your math looks clean. You just proved that both statement combined are INSUFF (in the extreme case).
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yezz
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Are atleast 20 percent of the people in city H who are at least 30 years old bilingual?

1. In city H, 30 percent of the population is at least 30 years old.
2. In city H, of the population 30 years old or older, 18 percent of the women and 17 percent of the men are bilingual

LET THE POPULATION = 1000
FROM ONE

300 ARE AT LEAST 30 YEARS OLD......INSUFF

FROM TWO

FROM 300 18% 0F WOMEN ( WHICH WE DONT KNOW ITS TOTAL) AND 17 % OF MEN ARE BILINGUAL

300 = W+M THUS 18%(300-M) = 54-0.18M ARE BILINGUAL

AND 17% OF M ARE BILINGUAL = 0.17M

TOTAL BILINGUAL = 54 - 0.35M

54-0.35M / 300 = 0.18 - 0.001167M THUS SURE IT WOULD BE LESS THAN 20 PERCENT

MY ANSWER IS C
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EconGirl
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I think it is B.

we don't have 20% of male nor female so we can't get 20% of total.
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I agree with B
the question is : Are 20% of cityH's population which is 30 years or older bilinual

solution B says that people of 30 years or older have following split up:
18% of the women and 17% men who are bilingual
now no matter what is the absolute no of men or women they can cross the 20% of the population....hence I will go with B and the ans to this question:
Are 20% of cityH's population which is 30 years or older bilinual
is NO...though we dont really care for it.



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