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# Are the numbers k/4, z/3, and r/2 in increasing order?

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Math Expert
Joined: 02 Sep 2009
Posts: 52297
Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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15 Dec 2014, 07:50
00:00

Difficulty:

65% (hard)

Question Stats:

59% (01:58) correct 41% (01:59) wrong based on 115 sessions

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Tough and Tricky questions: Number Properties.

Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k

Kudos for a correct solution.

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Manager
Joined: 10 Sep 2014
Posts: 97
Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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15 Dec 2014, 08:07
1
K/4 < Z/3 < R/2 ??

statement 1: insufficient
No info on k or r

statement 2: insufficient
If R=3, Z=4, and K=5, we get 1.20 < 1.25 < 1.50, increasing order
If R=-5, Z=-4, and K=-3, we get -3/4 < -4/3 < -5/2, not increasing order

statements 1+2: insufficient
If r=2, z=3.5, and k=10, we get 2.5 < 7/6 < 1, not increasing order
If r=3, z=3.5, k=4, we get 1<7/6<1.5, increasing order

Intern
Joined: 11 Feb 2018
Posts: 30
Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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27 Apr 2018, 05:30
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Number Properties.

Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k

Kudos for a correct solution.

Hi Bunuel

just a silly doubt i have....if u can plz help

if r/2>z/3>k/4 is given.....i can write it as 6r/12>4z/12>3k/12.. ?

Math Expert
Joined: 02 Sep 2009
Posts: 52297
Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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27 Apr 2018, 08:37
cruiseav wrote:
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Number Properties.

Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k

Kudos for a correct solution.

Hi Bunuel

just a silly doubt i have....if u can plz help

if r/2>z/3>k/4 is given.....i can write it as 6r/12>4z/12>3k/12.. ?

Yes, $$\frac{r}{2}>\frac{z}{3}>\frac{k}{4}$$ is equivalent to $$\frac{6r}{12}>\frac{4z}{12}>\frac{3k}{12}$$, which is the same as $$6r > 4z>3k$$ (you can get this by multiplying the first inequality by 12, which is the least common multiple of 2, 3, and 4).
_________________
Re: Are the numbers k/4, z/3, and r/2 in increasing order? &nbs [#permalink] 27 Apr 2018, 08:37
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# Are the numbers k/4, z/3, and r/2 in increasing order?

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