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Are the numbers k/4, z/3, and r/2 in increasing order?

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Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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New post 15 Dec 2014, 08:50
4
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A
B
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E

Difficulty:

  65% (hard)

Question Stats:

59% (01:58) correct 41% (01:59) wrong based on 115 sessions

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Tough and Tricky questions: Number Properties.



Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k


Kudos for a correct solution.
Spoiler: OA

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Collection of Questions:
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Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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New post 15 Dec 2014, 09:07
1
K/4 < Z/3 < R/2 ??

statement 1: insufficient
No info on k or r

statement 2: insufficient
If R=3, Z=4, and K=5, we get 1.20 < 1.25 < 1.50, increasing order
If R=-5, Z=-4, and K=-3, we get -3/4 < -4/3 < -5/2, not increasing order

statements 1+2: insufficient
If r=2, z=3.5, and k=10, we get 2.5 < 7/6 < 1, not increasing order
If r=3, z=3.5, k=4, we get 1<7/6<1.5, increasing order

Answer E!
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Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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New post 27 Apr 2018, 06:30
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Number Properties.



Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k


Kudos for a correct solution.


The correct answer is E.


Hi Bunuel

just a silly doubt i have....if u can plz help

if r/2>z/3>k/4 is given.....i can write it as 6r/12>4z/12>3k/12.. ?

thanks in advance...!!!
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Re: Are the numbers k/4, z/3, and r/2 in increasing order?  [#permalink]

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New post 27 Apr 2018, 09:37
cruiseav wrote:
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Number Properties.



Are the numbers k/4, z/3, and r/2 in increasing order?

(1) 3 < z < 4
(2) r < z < k


Kudos for a correct solution.


The correct answer is E.


Hi Bunuel

just a silly doubt i have....if u can plz help

if r/2>z/3>k/4 is given.....i can write it as 6r/12>4z/12>3k/12.. ?

thanks in advance...!!!


Yes, \(\frac{r}{2}>\frac{z}{3}>\frac{k}{4}\) is equivalent to \(\frac{6r}{12}>\frac{4z}{12}>\frac{3k}{12}\), which is the same as \(6r > 4z>3k\) (you can get this by multiplying the first inequality by 12, which is the least common multiple of 2, 3, and 4).
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

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Re: Are the numbers k/4, z/3, and r/2 in increasing order? &nbs [#permalink] 27 Apr 2018, 09:37
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