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02 Sep 2012, 18:44
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Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries?
A. 35
B. 40
C. 45
D. 50
E. 60
A. 35
B. 40
C. 45
D. 50
E. 60
03 Sep 2012, 05:52
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saurabhsingh24
Let's denote by:
R - number of red boxes
s - number of strawberries in each red box
B - number of blue boxes
b - number of blueberries in each blue box
We can write the following equations:
Rs + Bb + 25 = (R + 1)s + (B - 1)b and
Rs - Bb + 95 = (R + 1)s - (B - 1)b
or
s - b = 25
s + b = 95
Subtracting the first equation from the second, we obtain 2b = 70, or b = 35.
Answer A.
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