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Karanjotsingh
Given Information:
  • Arun and Sylvia start at the same point, running in the same direction.
  • Sylvia runs faster, reaches the far end, turns around, and then meets Arun while running back.

We are tasked with determining the length of the track.

Analyzing Statement (1): Sylvia ran twice as fast as Arun.

If Sylvia's speed is \( 2x \) and Arun's speed is \( x \), Sylvia completes the entire track and starts running back before meeting Arun. However, this statement alone does not provide any specific numerical information about the distance of the track.

  • Conclusion for Statement (1): NOT sufficient.


Analyzing Statement (2): Arun was 400 feet from the far end of the track when they met.

This gives us a numerical piece of information, but it does not provide the relative speeds of Arun and Sylvia, which are necessary to determine how much of the track Sylvia covered before meeting Arun.

  • Conclusion for Statement (2): NOT sufficient.

Combining Statements (1) and (2):

Now, we know:
  • Sylvia runs twice as fast as Arun (\( 2x \) vs \( x \)).
  • Arun is 400 feet from the far end of the track when they meet.

Using their relative speeds, we can calculate how much distance each covered before meeting. Let the total length of the track be \( d \):
1. The time taken by Arun to cover \( d - 400 \) is equal to the time taken by Sylvia to cover \( d + (d - 400) \), since Sylvia reaches the end and starts running back.

We can now set up the relationship:

\(\text{Time taken by Arun} = \text{Time taken by Sylvia}\)

\(\frac{d - 400}{x} = \frac{d + (d - 400)}{2x}\)

Solve this equation to find \( d \). Combining the statements allows us to find a unique value for the track's length.

Conclusion for Statements (1) and (2) TOGETHER: SUFFICIENT.


Final Answer:
C. BOTH statements TOGETHER are sufficient, but neither alone is.
\(\frac{d - 400}{x} = \frac{d + (d - 400)}{2x}\)

This statement doesn't give any solution.

So rather it should be:

\(\frac{d - 400}{x} = \frac{d +400)}{2x}\)

Hence d=1200. And this works.

Just adding as a reference for the concept.
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