Apr 20 10:00 PM PDT  11:00 PM PDT The Easter Bunny brings … the first day of school?? Yes! Now is the time to start studying for the GMAT if you’re planning to apply to Round 1 of fall MBA programs. Get a special discount with the Easter sale! Apr 21 07:00 AM PDT  09:00 AM PDT Get personalized insights on how to achieve your Target Quant Score. Apr 20 07:00 AM PDT  09:00 AM PDT Christina scored 760 by having clear (ability) milestones and a trackable plan to achieve the same. Attend this webinar to learn how to build trackable milestones that leverage your strengths to help you get to your target GMAT score. Apr 21 10:00 PM PDT  11:00 PM PDT $84 + an extra $10 off for the first month of EMPOWERgmat access. Train to be ready for Round 3 Deadlines with EMPOWERgmat's Score Booster. Ends April 21st Code: GCENHANCED Apr 22 08:00 AM PDT  09:00 AM PDT What people who reach the high 700's do differently? We're going to share insights, tips, and strategies from data we collected on over 50,000 students who used examPAL. Save your spot today! Apr 23 08:00 PM EDT  09:00 PM EDT Strategies and techniques for approaching featured GMAT topics. Tuesday, April 23rd at 8 pm ET Apr 24 08:00 PM EDT  09:00 PM EDT Maximize Your Potential: 5 Steps to Getting Your Dream MBA Part 3 of 5: Key TestTaking Strategies for GMAT. Wednesday, April 24th at 8 pm ET Apr 27 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. Apr 28 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes.
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 54376

At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
13 Feb 2015, 08:40
Question Stats:
86% (02:01) correct 14% (02:29) wrong based on 205 sessions
HideShow timer Statistics
At 1:00, Jack starts to bicycle along a 60 mile road at a constant speed of 15 miles per hour. Thirty minutes earlier, Scott started bicycling towards Jack on the same road at a constant speed of 12 miles per hour. At what time will they meet? A. 1:30 B. 3:00 C. 5:00 D. 6:00 E. 9:00 Kudos for a correct solution.
Official Answer and Stats are available only to registered users. Register/ Login.
_________________



Manager
Joined: 18 Aug 2014
Posts: 114
Location: Hong Kong

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
13 Feb 2015, 12:13
Bunuel wrote: At 1:00, Jack starts to bicycle along a 60 mile road at a constant speed of 15 miles per hour. Thirty minutes earlier, Scott started bicycling towards Jack on the same road at a constant speed of 12 miles per hour. At what time will they meet?
A. 1:30 B. 3:00 C. 5:00 D. 6:00 E. 9:00
Kudos for a correct solution. 13:30 Scott 12m 14:30 Scott 24m 15:30 Scott 36m > 15:00 Scott 36  6m = 30m 14:00 Jack 15m 15:00 Jack 30m Answer B



Math Expert
Joined: 02 Aug 2009
Posts: 7570

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
13 Feb 2015, 21:42
Bunuel wrote: At 1:00, Jack starts to bicycle along a 60 mile road at a constant speed of 15 miles per hour. Thirty minutes earlier, Scott started bicycling towards Jack on the same road at a constant speed of 12 miles per hour. At what time will they meet?
A. 1:30 B. 3:00 C. 5:00 D. 6:00 E. 9:00
Kudos for a correct solution. IN THESE QUESTIONS WE FIND THE DISTANCE BETWEEN TWO WHEN BOTH ARE MOVING AND THEN FIND THE TIME IT TAKES THE FASTER ONE TO COVER THAT DISTANCE... Scott has already moved for half an hour so he is 12/2 miles ahead.. =6 miles jack covers 3 miles extra each hour when compared to scott... so he will cover 6 miles in 6/3=2 hours.. 2 hours after 1:00 is 3:00...ans B
_________________



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 13957
Location: United States (CA)

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
14 Feb 2015, 21:36
Hi All, This is an example of the 'Combined Rate' question; on Test Day, they're relatively rare (you'll probably see just 1) and they're usually written in a way that requires a certain amount of real "math" work to get to the correct answer. By using the answer choices in this question, you can actually AVOID most of the work though. In the first sentence, we know Jack's starting time (1pm), speed (15 mph) and distance (60 miles), so we can quickly figure out how long it would take Jack to travel the entire distance (4 hours). This tells us that, at 5pm, Jack would be at the other end of the road. We know that Scott is cycling TOWARDS him though, so some time BEFORE 5PM, they'll meet. Eliminate Answers C, D and E. With the remaining two answers, 1:30pm is much TOO early to be the meeting time. Neither Jack nor Scott is traveling fast enough to meet up that early. Eliminate A. There's only one answer left.. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com*****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*****
Rich Cohen
CoFounder & GMAT Assassin
Special Offer: Save $75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/



Intern
Joined: 23 Oct 2014
Posts: 3

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
15 Feb 2015, 12:01
let x be time.
15x+12(x+1/2)=60; 27x=54; x=2;
=>
1:00 + 2 hr = 3:00



Math Expert
Joined: 02 Sep 2009
Posts: 54376

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
16 Feb 2015, 06:27
Bunuel wrote: At 1:00, Jack starts to bicycle along a 60 mile road at a constant speed of 15 miles per hour. Thirty minutes earlier, Scott started bicycling towards Jack on the same road at a constant speed of 12 miles per hour. At what time will they meet?
A. 1:30 B. 3:00 C. 5:00 D. 6:00 E. 9:00
Kudos for a correct solution. VERITAS PREP OFFICIAL SOLUTIONCorrect Answer: B Explanation: Solution: B The relevant formula is Rate x Time = Distance. If Jack's time is t, then Scott's time is t + .5, since he started onehalf hour earlier. Jack's distance is therefore 15t, and Scott's distance is 12 (t + .5). The sum of their distances will be the distance apart that they started. Therefore we can say that 15t + 12 (t + .5) = 60. This simplifies to 15t + 12t + 6 = 60, which means that 27t = 54, and t = 2. Since Jack left at 1:00, and his time was t, he met Scott at 3:00.
_________________



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1813
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
19 Feb 2015, 01:59
Answer = B = 3:00 At 01:00, Scott has already travelled 6 kms, so remaining distance = 604 = 54 Say Jack meets Scott at "x" kms from his own starting point \(\frac{x}{15} = \frac{54x}{12}\) x = 30 Time required by Jack to travel 30kms = 2 Hrs They will meet at 03:00
_________________
Kindly press "+1 Kudos" to appreciate



Manager
Joined: 22 May 2015
Posts: 108

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
23 Jan 2017, 18:01
Given : Distance is 60 miles Scott has a 30 mins lead and hence covers 6 miles. So when Jack starts he and Scott have to cover a distance of 54miles ( 606) to reach each other, with a speed of 27 miles/hour ( 15+12 ) => 2 Hours, 1:00 + 2 hours = 3:00...
_________________



Manager
Joined: 25 Mar 2013
Posts: 238
Location: United States
Concentration: Entrepreneurship, Marketing
GPA: 3.5

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
08 Feb 2017, 11:12
Scott has already moved for half an hour so he is 12/2 miles ahead.. =6 miles jack covers 3 miles extra each hour when compared to scott... so he will cover 6 miles in 6/3=2 hours.. 2 hours after 1:00 is 3:00...ans B
_________________
I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you



Intern
Joined: 30 Jan 2017
Posts: 1

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
15 Feb 2017, 15:47
Scott is ahead by 30min x 12 miles per 60 min = 6 miles.
Find the relative speed of Jack to Scott, 15 miles/hr  12 miles/hr = 3 miles/hr
For Jack to catch up and meet Scott is 6 / 3 = 2 hrs
1:00 + 2 hrs = 3:00 = Answer



Manager
Joined: 03 Jan 2016
Posts: 57
Location: India
WE: Engineering (Energy and Utilities)

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
18 Mar 2017, 20:40
Distance Traveled by Jockey = 6 + Distance Traveled by Scott Lets Say they will meet after T hours. 15T = 12T + 6 T=2 Hours therefore, They Will meet @ 03:00 pm



Director
Joined: 12 Nov 2016
Posts: 725
Location: United States
GPA: 2.66

Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
Show Tags
13 Aug 2017, 20:57
Bunuel wrote: At 1:00, Jack starts to bicycle along a 60 mile road at a constant speed of 15 miles per hour. Thirty minutes earlier, Scott started bicycling towards Jack on the same road at a constant speed of 12 miles per hour. At what time will they meet?
A. 1:30 B. 3:00 C. 5:00 D. 6:00 E. 9:00
Kudos for a correct solution. 12(x + 1/2) +15x =60 27x =54 x=2 2 hours from 1 or 2 hours and 30 mins from 12 :30 B




Re: At 1:00, Jack starts to bicycle along a 60 mile road at a constant spe
[#permalink]
13 Aug 2017, 20:57






