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06 Nov 2024, 01:30
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
80% (02:57) correct
20%
(02:55)
wrong
based on 330
sessions
History
Date
Time
Result
Not Attempted Yet
At a certain automobile dealership that sells only Tajimas and Franks, the number of nonhybrid Tajimas is 35 less than 3 times the number of hybrid Tajimas. 205 total Tajimas are currently owned by the dealership. If the ratio of hybrid Tajimas to nonhybrid Franks is 5:4 and there are 280 total automobiles owned by the dealership, how many hybrid Franks are there?
A. 20
B. 27
C. 48
D. 60
E. 87
A. 20
B. 27
C. 48
D. 60
E. 87
06 Nov 2024, 03:41
Kudos
Bookmarks
Used 2*2 matrix for this
........... T ........... F .... Total
NH.... 3h-35 .......... f .....
H.......h................. Ans..
Tot....205.............. 75......280
\(\\
3h-35+h=205\\
h=60\\
\)
\(\frac{60}{f}=\frac{5}{4}\)
\(f=48\)
\(Answer= 75-48= 27\) (B)
........... T ........... F .... Total
NH.... 3h-35 .......... f .....
H.......h................. Ans..
Tot....205.............. 75......280
\(\\
3h-35+h=205\\
h=60\\
\)
\(\frac{60}{f}=\frac{5}{4}\)
\(f=48\)
\(Answer= 75-48= 27\) (B)
06 Nov 2024, 09:52
Kudos
Bookmarks
Nonhybrid Tajimas (NHT)= 3 Hybrid Tajimas-35
NHT= 3*HT-35.............(1)
HT+NHT=205.............(2)
Placing value of NHT in (2)
HT+3(HT)-35=205
4*HT=205+35
HT=240/4= 60 & NHT=205-60= 145 ...........(3)
Total automobiles= 280
Number of Franks (F)= 280-205= 75
HT:NHF=5:4
HT/NHF=5/4=60/NHF..........(From (3), HT=60)
NHF= (60*4)/5
NHF= 48
HF= F-NHF= 75-48= 27
Answer: B
NHT= 3*HT-35.............(1)
HT+NHT=205.............(2)
Placing value of NHT in (2)
HT+3(HT)-35=205
4*HT=205+35
HT=240/4= 60 & NHT=205-60= 145 ...........(3)
Total automobiles= 280
Number of Franks (F)= 280-205= 75
HT:NHF=5:4
HT/NHF=5/4=60/NHF..........(From (3), HT=60)
NHF= (60*4)/5
NHF= 48
HF= F-NHF= 75-48= 27
Answer: B
