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# At a certain company, average (arithmetic mean)number of

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Re: At a certain company, average (arithmetic mean)number of [#permalink]
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We can use alligations for such kind of problems
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Re: At a certain company, average (arithmetic mean)number of [#permalink]
Let us assume the number of male employees in the company is m and number of female employees is f. Average number of years of experience for male employees is 9.8 and average number of years of experience for female employees is 9.1.
We need the ratio m:f.

Statement 1: m = 52
This is not enough to determine the ratio of m:f.

Not sufficient.

Statement 2: (9.8m + 9.1f)/(m + f) = 9.3
--> 9.8m + 9.1f = 9.3m + 9.3f.
--> 0.5m = 0.2f
--> m/f = m : f = 2:5

Sufficient

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Re: At a certain company, average (arithmetic mean)number of [#permalink]
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prashi82 wrote:
At a certain company, average (arithmetic mean) number of years of experience is 9.8 years for male employees and 9.1 years for the female employees. What is the ratio of the number of the company's male employees and the number of the company's female employees?

(1) There are 52 male employees at the company
(2) The average number of years of experience for the company's male and female employees combined is 9.3 years.

OA:B

Let Number of Male be $$M$$, and number of females be $$F$$

$$Av_{Male}$$ and $$Av_{Female}$$ be average number of years of experience of male and female respectively.

Given : $$Av_{Male} = 9.8\quad years ,Av_{Female}=9.1\quad years$$

We have to find the ratio $$\frac{M}{F}$$

Statement 1: There are 52 male employees at the company

It gives us value of $$M$$, But We do not have value of $$F$$.

So Statement 1 alone is insufficient to find the ratio $$\frac{M}{F}$$

Statement 2: The average number of years of experience for the company's male and female employees combined is 9.3 years.

$$\frac{M*Av_{Male}+F*Av_{Female}}{M+F}=9.3$$

$$9.8M+9.1F=9.3(M+F)$$

Dividing both sides by $$F$$, we get

$$9.8\frac{M}{F}+9.1=9.3(\frac{M}{F}+1)$$

We can find the value of $$\frac{M}{F}$$

Statement 2 alone is sufficient
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Re: At a certain company, average (arithmetic mean)number of [#permalink]
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Re: At a certain company, average (arithmetic mean)number of [#permalink]
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