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At a monthly meeting, 2/5 of the attendees were males and 7/
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28 Jan 2014, 02:03
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The Official Guide For GMAT® Quantitative Review, 2ND EditionAt a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time? (A) 11/100 (B) 3/25 (C) 7/50 (D) 3/20 (E) 4/25 Problem Solving Question: 64 Category: Arithmetic Operations with rational numbers Page: 70 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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SOLUTIONAt a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?(A) 11/100 (B) 3/25 (C) 7/50 (D) 3/20 (E) 4/25 Assume the total number of attendees =100. Males = 2/5*100 = 40; Females = 100  40 = 60. On time males = 7/8*40 = 35; On time female = 9/10*60 = 54. Total on time attendees = 35 + 54 = 89; Not on time = 100  89 = 11. Fraction = 11/100. Answer: A.
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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28 Jan 2014, 04:09
Set the total number of employees equal to a smart number like 100. Set up a table as attached and plug in the info in the question. The answer is therefore 11/100. Answer A
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File comment: table of workings
Workbook.xlsx [9.04 KiB]
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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28 Jan 2014, 08:48
Assume a number 100.. 2/5 male...that means 40...from that 7/8 means 35=(40*7/8) arrives on time. 40 wud be female..from that 9/10 means..54 arrive on time 35+54=89 arrives on time..11 out of 100 didn't arrive on time.. So A is the answer..
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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28 Jan 2014, 11:22
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionAt a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time? (A) 11/100 (B) 3/25 (C) 7/50 (D) 3/20 (E) 4/25 let the total attendees be T . 2/5T = male attendees and therefore it can be derived that 3/5T = women attendees. 7/8 * 2/5T = 7/20T = male attendees who arrived on time. therefore: 1/8 * 2/5 = 1/20 male attendees were late 9/10*3/5T =27/50T = women attendees who came on time. therefore 1/10 * 3/5 = 3/50 were women attendess who came late. therefore adding both the numbers of attendees who were late : (1/20 + 3/50 )T = (5+6)/100=11/100 So, IMO A.



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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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28 Jan 2014, 22:59
This is a good question for picking numbers; Probably, a multiple of the denominators: 5 * 8 * 10 = 400;
Let us assume the total no. of attendees to be 400; No. of males = (2/5) * 400 = 160; Therefore, No. of females = 240; No. of male attendees arrived on time = (7/8) * 160 = 140; Therefore, no. of male attendees who did not arrive on time = 20;
We need to find the fraction of attendees who did not arrive on time: So, (1/10)th of the female attendees did not arrive on time = (1/10) * 240 = 24;
20 + 24 = 44; => Total no. of attendees, including male and female, who did not arrive on time = 44;
The fraction = 44/400 = 11/100.(We can stop here and pick Answer A. Suppose, if the aswer were in percentages, it would be 11%).
Ans is (A).



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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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29 Jan 2014, 03:24
Assuming total no. of members to be 40(multiple of 5 and 8) we get no of males=16 and females=24 On time males=14 Not on time males=2 On time females=216/10 and not on time females=24/10 Adding 2+24/10=44/10*1/40=11/100 Ans A



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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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29 Jan 2014, 22:38
1) Fraction of late males: 1/8 (8/87/8) 2) Fraction of late females: 1/10 (10/109/10)
(1/8 * 2/5) + (1/10 * 3/5) = 22/200 = 11/100, so (A).



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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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02 Feb 2014, 07:24
sanjoo wrote: Assume a number 100..
2/5 male...that means 40...from that 7/8 means 35=(40*7/8) arrives on time.
40 wud be female..from that 9/10 means..54 arrive on time
35+54=89 arrives on time..11 out of 100 didn't arrive on time.. So A is the answer.. No of females should be 60.



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Re: At a monthly meeting, 2/5 of the attendees were males and 7/
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02 Feb 2014, 07:38
At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?
(A) 11/100 (B) 3/25 (C) 7/50 (D) 3/20 (E) 4/25
Let total attendees be \(x\)
Male attendees \(= \frac{2}{5}x\)
Then, Female attendees\(= \frac{3}{5}x\)
Given that \(\frac{7}{8}\) of male attendees & \(\frac{9}{10}\) of female attendees arrive on time.
So, attendees did not arrive on time \(= x  ((\frac{2}{5})(\frac{7}{8}) + (\frac{3}{5})(\frac{9}{10}))x = (\frac{11}{100})x\)
Answer: (A)



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Re: At a monthly meeting, 2/5 of the attendees were males and
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15 Mar 2018, 10:13
goalsnr wrote: At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?
A. 11/100 B. 3/25 C. 7/50 D. 3/20 E. 4/25 We can let the total number of attendees = 800. (This is a convenient number that allows the calculations to be easier.) Thus, there are 2/5 x 800 = 320 males and 800  320 = 480 females. Since 7/8 of the males arrived on time, 7/8 x 320 = 280 males arrived on time. Since 9/10 of the female attendees arrived on time, 9/10 x 480 = 432 females arrived on time. Thus, 800  (280 + 432) = 88 attendees did not arrive on time. Therefore, the fraction of the attendees who did not arrive on time is 88/800 = 11/100. Answer: A
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