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# At a monthly meeting, 2/5 of the attendees were males and 7/

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Math Expert
Joined: 02 Sep 2009
Posts: 58327
At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 02:03
2
8
00:00

Difficulty:

5% (low)

Question Stats:

88% (02:17) correct 12% (02:47) wrong based on 437 sessions

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

(A) 11/100
(B) 3/25
(C) 7/50
(D) 3/20
(E) 4/25

Problem Solving
Question: 64
Category: Arithmetic Operations with rational numbers
Page: 70
Difficulty: 600

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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 02:03
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SOLUTION

At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

(A) 11/100
(B) 3/25
(C) 7/50
(D) 3/20
(E) 4/25

Assume the total number of attendees =100.

Males = 2/5*100 = 40;
Females = 100 - 40 = 60.

On time males = 7/8*40 = 35;
On time female = 9/10*60 = 54.

Total on time attendees = 35 + 54 = 89;
Not on time = 100 - 89 = 11.

Fraction = 11/100.

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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 04:09
1
Set the total number of employees equal to a smart number like 100. Set up a table as attached and plug in the info in the question.

The answer is therefore 11/100.

Attachments

File comment: table of workings
Workbook.xlsx [9.04 KiB]

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Posts: 318
Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 08:48
1
Assume a number 100..

2/5 male...that means 40...from that 7/8 means 35=(40*7/8) arrives on time.

40 wud be female..from that 9/10 means..54 arrive on time

35+54=89 arrives on time..11 out of 100 didn't arrive on time.. So A is the answer..
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 11:22
1
1
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

(A) 11/100
(B) 3/25
(C) 7/50
(D) 3/20
(E) 4/25

let the total attendees be T .
2/5T = male attendees and therefore it can be derived that 3/5T = women attendees.
7/8 * 2/5T = 7/20T = male attendees who arrived on time. therefore: 1/8 * 2/5 = 1/20 male attendees were late
9/10*3/5T =27/50T = women attendees who came on time. therefore 1/10 * 3/5 = 3/50 were women attendess who came late.

therefore adding both the numbers of attendees who were late : (1/20 + 3/50 )T = (5+6)/100=11/100

So, IMO A.
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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28 Jan 2014, 22:59
1
This is a good question for picking numbers;
Probably, a multiple of the denominators: 5 * 8 * 10 = 400;

Let us assume the total no. of attendees to be 400;
No. of males = (2/5) * 400 = 160; Therefore, No. of females = 240;
No. of male attendees arrived on time = (7/8) * 160 = 140; Therefore, no. of male attendees who did not arrive on time = 20;

We need to find the fraction of attendees who did not arrive on time: So, (1/10)th of the female attendees did not arrive on time = (1/10) * 240 = 24;

20 + 24 = 44; => Total no. of attendees, including male and female, who did not arrive on time = 44;

The fraction = 44/400 = 11/100.(We can stop here and pick Answer A. Suppose, if the aswer were in percentages, it would be 11%).

Ans is (A).
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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29 Jan 2014, 03:24
1
Assuming total no. of members to be 40(multiple of 5 and 8) we get no of males=16 and females=24
On time males=14
Not on time males=2
On time females=216/10
and not on time females=24/10
Ans A
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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29 Jan 2014, 22:38
1
1) Fraction of late males: 1/8 (8/8-7/8)
2) Fraction of late females: 1/10 (10/10-9/10)

(1/8 * 2/5) + (1/10 * 3/5) = 22/200 = 11/100, so (A).
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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02 Feb 2014, 07:24
sanjoo wrote:
Assume a number 100..

2/5 male...that means 40...from that 7/8 means 35=(40*7/8) arrives on time.

40 wud be female..from that 9/10 means..54 arrive on time

35+54=89 arrives on time..11 out of 100 didn't arrive on time.. So A is the answer..

No of females should be 60.
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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02 Feb 2014, 07:38
At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

(A) 11/100
(B) 3/25
(C) 7/50
(D) 3/20
(E) 4/25

Let total attendees be $$x$$

Male attendees $$= \frac{2}{5}x$$

Then, Female attendees$$= \frac{3}{5}x$$

Given that $$\frac{7}{8}$$ of male attendees & $$\frac{9}{10}$$ of female attendees arrive on time.

So, attendees did not arrive on time $$= x - ((\frac{2}{5})(\frac{7}{8}) + (\frac{3}{5})(\frac{9}{10}))x = (\frac{11}{100})x$$

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Re: At a monthly meeting, 2/5 of the attendees were males and  [#permalink]

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15 Mar 2018, 10:13
1
goalsnr wrote:
At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

A. 11/100
B. 3/25
C. 7/50
D. 3/20
E. 4/25

We can let the total number of attendees = 800. (This is a convenient number that allows the calculations to be easier.)

Thus, there are 2/5 x 800 = 320 males and 800 - 320 = 480 females.

Since 7/8 of the males arrived on time, 7/8 x 320 = 280 males arrived on time.

Since 9/10 of the female attendees arrived on time, 9/10 x 480 = 432 females arrived on time.

Thus, 800 - (280 + 432) = 88 attendees did not arrive on time.

Therefore, the fraction of the attendees who did not arrive on time is 88/800 = 11/100.

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Re: At a monthly meeting, 2/5 of the attendees were males and 7/  [#permalink]

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21 Aug 2019, 08:44
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Re: At a monthly meeting, 2/5 of the attendees were males and 7/   [#permalink] 21 Aug 2019, 08:44
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