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At a particular company, the average income of managers is $50,000
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08 Nov 2018, 03:33
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53% (02:19) correct 47% (02:28) wrong based on 62 sessions
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At a particular company, the average income of managers is $50,000 more than the average of all the employees. The average income of salespeople is $25,000 less than the average of all of the employees. What is the ratio of managers to saleseople? A) 2:1 B) 3:2 C) 4:3 D) 1:2 E) 1:4
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Re: At a particular company, the average income of managers is $50,000
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08 Nov 2018, 03:43
M/ S = (Difference of sales person from all avg)/ (Difference of managers from all ) =25000/50000 1:2 Answer: D For above here is formula:
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At a particular company, the average income of managers is $50,000
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12 Nov 2018, 06:05
Abhi077 wrote: At a particular company, the average income of managers is $50,000 more than the average of all the employees. The average income of salespeople is $25,000 less than the average of all of the employees. What is the ratio of managers to saleseople? A) 2:1 B) 3:2 C) 4:3 D) 1:2 E) 1:4 Dear GMATGuruNYCan you share your thoughts in solving such problem? Thanks in advance



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Re: At a particular company, the average income of managers is $50,000
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12 Nov 2018, 06:48
Mo2men wrote: Abhi077 wrote: At a particular company, the average income of managers is $50,000 more than the average of all the employees. The average income of salespeople is $25,000 less than the average of all of the employees. What is the ratio of managers to saleseople? A) 2:1 B) 3:2 C) 4:3 D) 1:2 E) 1:4 Dear GMATGuruNYCan you share your thoughts in solving such problem? Thanks in advance Let the average salary of all the employees = 50,000, implying that the average salary of the managers = 50,000 + 50,000 = 100,000 and that the average salary of the salespeople = 50,000  25,000 = 25,000. To determine the ratio of managers to salespeople, use alligation. Step 1: Draw a number line, with the averages for the managers and salespeople on the ends and the average for all the employees in the middle:M 100,00050,00025,000 S Step 2: Calculate the distances between the averages.M 100,000 50,00050,000 25,00025,000 S Step 3: Determine the ratio in the mixture.The ratio of M to S is equal to the RECIPROCAL of the distances in red. M:S = 25000:50000 = 1:2
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Re: At a particular company, the average income of managers is $50,000
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19 Jun 2019, 06:02
Abhi077 wrote: At a particular company, the average income of managers is $50,000 more than the average of all the employees. The average income of salespeople is $25,000 less than the average of all of the employees. What is the ratio of managers to saleseople? A) 2:1 B) 3:2 C) 4:3 D) 1:2 E) 1:4 Easiest way to take this on is consider the average to be any value, let's take $100,000, for the ease of calculation, now we have the average income of managers = $150,000, and the average income of salespeople to be $75,000 Let the number of managers and salespeople be M and S respectively Now we have, total sum of the income of managers to be 150000*M and total sum of the income of salespeople to be 75000*S Simply putting in the formula for average, average of all employees = $100,000 = Total Sum of All Employees / Total No. of Employees (150000*M + 75000*S) divided by (M + S) $100,000 = (150000*M + 75000*S) divided by (M + S) Multiplying both sides by (M+S), we get $100,000*(M+S) = 150000*M + 75000*S Solving this, we get 25000*S = 50000 * M And solving further, we get M/S = 1/2 (D) HIT KUDOS IF YOU LIKE MY SOLUTION



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Re: At a particular company, the average income of managers is $50,000
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21 Jun 2019, 10:54
Abhi077 wrote: At a particular company, the average income of managers is $50,000 more than the average of all the employees. The average income of salespeople is $25,000 less than the average of all of the employees. What is the ratio of managers to saleseople? A) 2:1 B) 3:2 C) 4:3 D) 1:2 E) 1:4 We can let n = the average income of all employees, s = the number of salespeople and m = the number of managers, and create the following equation (we assume there are no employees other than managers and salespeople): n = [m(50,000 + n) + s(n  25,000)]/(m + s) mn + ns = 50,000m + mn + sn  25,000s 25,000s = 50,000m 25,000/50,000 = m/s 1/2 = m/s Answer: D
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Re: At a particular company, the average income of managers is $50,000
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