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# At a two-candidate election for mayor, 3/4 of the registered voters ca

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Re: At a two-candidate election for mayor, 3/4 of the registered voters ca [#permalink]
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fozzzy wrote:
is this a venn diagram question / double matrix? If it is how would set up the table?

No it is not, because we do not have overlapping sets. We cannot have a voter who cast the ballot for both candidates. It's a simple word problem.

At a two-candidate election for mayor, 3/4 of the registered voters cast ballots. How many registered voters cast ballots for the winning candidate?

3/4 of the registered voters cast ballots and 1/4 of the registered voters did NOT cast ballots.

(1) 25000 registered voters did not cast ballots in the election --> 25,000 registered voters = 1/4 of the registered voters, thus there are total of 4*25,000=100,000 registered voters and 75,000 of them cast ballots. We don;t know how those people voted. Not sufficient.

(2) Of the registered voters who cast ballots, 55 percent cast ballots for the winning candidate. We know only percentage. Not sufficient.

(1)+(2) 0.55*75,000=41,250 registered voters cast ballots for the winning candidate. Sufficient.

Hope it's clear.
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Re: At a two-candidate election for mayor, 3/4 of the registered voters ca [#permalink]
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Re: At a two-candidate election for mayor, 3/4 of the registered voters ca [#permalink]
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