Bunuel
At a wildlife sanctuary, researchers track the survival of two newly released animal groups. Group A has a 3/5 chance of surviving its first winter, while Group B has a 4/5 chance of surviving its first winter.
Select for
Minimum Survival the lowest probability, consistent with these estimates, that both groups survive the winter. Select for
Maximum Survival the highest probability, consistent with these estimates, that both groups survive the winter. Make only two selections, one in each column.
• Minimum Survival ProbabilityWe use the equation:
Total = P(A) + P(B) – P(both) + P(neither).
Substitute the values:
1 = 3/5 + 4/5 – P(both) + P(neither).
P(both) = 2/5 + P(neither).
To minimize P(both), we set P(neither) = 0.
This gives P(both) = 2/5.
Alternative we can do the following:We are given:
P(A) = 3/5 (the probability that Group A survives),
P(B) = 4/5 (the probability that Group B survives).
This means the probability that Group B does not survive is:
P(not B) = 1 - P(B) = 1/5.
Now consider the event “A survives
and B does not survive.” Its probability cannot be greater than either P(A) = 3/5 or P(not B) = 1/5. Therefore, the
maximum possible probability of this event, “A survives
and B does not survive”, is 1/5.
But P(A) = 3/5 represents all cases where A survives, and that breaks into two disjoint parts:
A survives and B survives, and
A survives and B does not survive.
So we can write:
P(A) = P(A and B) + P(A and not B).
We know P(A) = 3/5, and the maximum possible value of P(A and not B) is 1/5.
Therefore, the minimum possible value of P(A and B) is:
P(A and B) = 3/5 - 1/5 = 2/5.
So by this reasoning as well, the minimum survival probability for both is 2/5.
• Maximum Survival ProbabilityThe probability of Group A surviving is 3/5 (60%) and the probability of Group B surviving is 4/5 (80%). The maximum probability that both survive cannot be greater than either one individually. Therefore, the maximum possible value of P(both) is the smaller of the two: 3/5 (60%).
I29-168