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Bunuel
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Given info
P(A)=3/5=0.6
P(NOT A)=2/5=0.4

P(B)=4/5=0.8
P(NOT B)=1/5=0.2

Lets form a table to check max and min probability and mark


MAX PROBABILITYP(A)P(NOT A)TOTAL
P(B)0.600.20.8
P(NOT B)00.20.2
TOTAL0.600.401


MIN PROBABILITYP(A)P(NOT A)TOTAL
P(B)0.400.40.8
P(NOT B)0.200.2
TOTAL0.600.401

So max P(A&B)=0.6=3/5
So min P(A&B)=0.4=2/5

hope it helps
Bunuel
At a wildlife sanctuary, researchers track the survival of two newly released animal groups. Group A has a 3/5 chance of surviving its first winter, while Group B has a 4/5 chance of surviving its first winter.

Select for Minimum Survival the lowest probability, consistent with these estimates, that both groups survive the winter. Select for Maximum Survival the highest probability, consistent with these estimates, that both groups survive the winter. Make only two selections, one in each column.
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Is not the prob of both surviving 12/25?
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Is not the prob of both surviving 12/25?

12/25 is what you get if you assume independence (multiply 3/5 * 4/5).

But the problem never says the two groups’ survival outcomes are independent. Without that assumption, you have to consider all possible correlations. That’s why the solution gives a range: the minimum consistent value is 2/5, and the maximum is 3/5.

So 12/25 is just one possible value inside that range, not the guaranteed answer.
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